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sertanlavr [38]
1 year ago
14

A parabola is represented by the equation y2 = 5x. which equation represents the directrix?

Mathematics
1 answer:
ivann1987 [24]1 year ago
7 0

The value of the directrix is -5/4.

According to the statement

we have given that the equation of parabola is y2 = 5x. And we have to find that the which equation represents the directrix.

We know that the general equation of parabola is

(y - k)2 = 4a(x - h)  -(1)

and given parabola equation is

y2 = 5x.  -(2)

After comparing the both equations we get k=0 and h=0

And the formula to find the directrix is

x = h - a

Substitute the values of h and a in it then

x = 0-5/4

x = -5/4.

Here the directrix is -5/4.

So, The value of the directrix is -5/4.

Learn more about the Parabola here brainly.com/question/4061870

#SPJ4

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The zeroes of the function will be \rm -1 \pm \dfrac{\sqrt{78}}{6}}

<h3>What is a Quadratic Function ?</h3>

A quadratic function is given by ax² +bx+c = f(x)

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The zeroes of the function will be given by

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The zeroes are given by

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\rm \dfrac {-12  \pm \sqrt{312}}{12}

\rm -1 \pm \dfrac{\sqrt{78}}{6}}

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A phycologist is interested in determining the proportion of algae samples from a local rivulet that belong to a particular phyl
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Answer:

A sample of 16577 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

She wants to estimate the proportion using a 99% confidence interval with a margin of error of at most 0.01. How large a sample size would be required?

We have no estimation for the proportion, and thus we use \pi = 0.5, which is when the largest sample size will be needed.

The sample size is n for which M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 2.575\sqrt{\frac{0.5*0.5}{n}}

0.01\sqrt{n} = 2.575*0.5

\sqrt{n} = \frac{2.575*0.5}{0.01}

(\sqrt{n})^2 = (\frac{2.575*0.5}{0.01})^2

n = 16576.6

Rounding up:

A sample of 16577 is required.

8 0
2 years ago
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