Let w bet the number of white cars and y the numbers of yellow cars.
"Rafael counted a total of 40 white and yellow cars" So w+y = 40.
"There were 9 times as many white cars as yellow cars" So 9Y = W
We get the system:
w+y=40 (1)
9y=w (2)
In equation (1), let's replace w by it's value from equation (2) since w=9y.
We get: 9y+y = 40
10y=40
y=4
So there's 4 yellow cars.
In equation (1), let's replace y by it's value
w+4=40
w=40-4
w=36
Rafael counted 36 white cars.
You can re-check your answer:
4+36=40 (w+y=40)
9*4=36 (9y=w)
The answer has been approved.
Hope this Helps! :)
Answer:
You would need 2.5
Step-by-step explanation:
You can use a porportion to solve.
(cross multiply and solve)
Answer:
C
a = 1 : b=-8; C = 12
Step-by-step explanation:
I think you did not include the sign between the x^2 and the 8x...my guess is that it is a minus.
By process of elimination the answer is not B or D bc the a-value is 1 not 0.
Then the +12 you did include in the original question indicates that the c-value is 12 not -12 eliminating answer A.
25 > 2x + 8 - 66
first simplify all numbers
25 > 2x + (8 - 66)
25 > 2x - 58
Then add 58 to both sides
25 (+58) > 2x - 58 (+58)
83 > 2x
Finally divide 2 from both sides to isolate the x
83/2 > 2x/2
41.5 > x
hope this helps
