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2 years ago

Please solve this Solve by completing the square. 4x2+8x−3=0

Mathematics

1 answer:

Greeley [361]2 years ago

7 0

Step-by-step explanation:

4x2+8x−3=0

For this equation: a=4, b=8, c=-3

4x2+8x+−3=0

Step 1: Use quadratic formula with a=4, b=8, c=-3.

−b±√b2−4ac

x= −(8)±√(8)2−4(4)(−3)

2(4)

x= −8±√112

8 x=−1+

1 2 √7 or x=−1+

−1 2 √7

Answer: x=−1+

1 2√7 or x=−1+

−1 2 √7

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Find the distance to the nearest tenth,between S(6,5) and T(-3,-4)

Doss [256]

Answer:

<h3>The answer is 12.7 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

S(6,5) and T(-3,-4)

The distance between them is

$|ST| = \sqrt{ ({6 + 3})^{2} + ({5 + 4})^{2} } \\ = \sqrt{ {9}^{2} + {9}^{2} } \\ = \sqrt{81 + 81} \\ = \sqrt{162} \\ = 9 \sqrt{2} \: \: \\ = 12.7279...$

We have the final answer as

<h3>12.7 units to the nearest tenth</h3>

Hope this helps you

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3 years ago

The package shown is shaped like a right rectangular prism. Every side of the package will be covered with gift wrap, except the

Alexxandr [17]

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3 years ago

Solve the problem, calculate the line integral of f along h

Over [174]

The curve $\mathcal H$ is parameterized by

$\begin{cases}X(t)=R\cos t\\Y(t)=R\sin t\\Z(t)=Pt\end{cases}$

so in the line integral, we have

$\displaystyle\int_{\mathcal H}f(x,y,z)\,\mathrm ds=\int_{t=0}^{t=2\pi}f(X(t),Y(t),Z(t))\sqrt{\left(\frac{\mathrm dX}{\mathrm dt}\right)^2+\left(\frac{\mathrm dY}{\mathrm dt}\right)^2+\left(\frac{\mathrm dZ}{\mathrm dt}\right)^2}\,\mathrm dt$
$=\displaystyle\int_0^{2\pi}Y(t)^2\sqrt{(-R\sin t)^2+(R\cos t)^2+P^2}\,\mathrm dt$
$=\displaystyle\int_0^{2\pi}R^2\sin^2t\sqrt{R^2+P^2}\,\mathrm dt$
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You are mistaken in thinking that the gradient theorem applies here. Recall that for a scalar function $f:\mathbb R^n\to\mathbb R$ , we have gradient $\nabla f:\mathbb R^n\to\mathbb R^n$ . The theorem itself then says that the line integral of $\nabla f(x,y,z)=\mathbf f(x,y,z)$ along a curve $C$ parameterized by $\mathbf r(t)$ , where $a\le t\le b$ , is given by

$\displaystyle\int_C\mathbf f(x,y,z)\,\mathrm d\mathbf r=f(\mathbf r(b))-f(\mathbf r(a))$

Specifically, in order for this theorem to even be considered in the first place, we would need to be integrating with respect to a vector field.

But this isn't the case: we're integrating $f(x,y,z)=y^2$ , a scalar function.

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3 years ago

11 ounces of tomato soup has 70 calories. How many calories are in 22 ounces of soup? *

fenix001 [56]

Answer:

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Step-by-step explanation:

We use ratio and proportion.

$\frac{11}{22} =\frac{70}{x}$

Cross multiply, and you get:

11x = 1,540

Divide both sides by 11. Thus:

140 ounces.

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Hello there, and thank you for posting your question here on brainly.

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3 years ago

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