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ZanzabumX [31]
2 years ago
6

Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0).

Mathematics
1 answer:
hichkok12 [17]2 years ago
8 0

Answer:im not sure

Step-by-step explanation:

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Given that the mass of an average linebacker at Ursinus College is 250 lbs and the radius of a pea is 0.50 cm, calculate the num
Brilliant_brown [7]

Answer:

1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle

Step-by-step explanation:

Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is

V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³

the mass in that volume would be  m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)

The density of an alpha particle is  ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be

ρ= m/V

since both should be equal ρ=ρa , then

ρa= m/V =N*L/V → N =ρa*V/L

replacing values

N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg  = 1.544*10⁹ Linebackers

N=1.544*10⁹ Linebackers

7 0
3 years ago
Help Please!!!!!!!!!!!!!
zheka24 [161]

Answer:

A. 2086 yd²

Step-by-step explanation:

SA = 2lw + 2wh + 2lh
SA = 2*17*20 + 2*20*19 + 2*17*19
SA = 680 + 760 + 646
SA = 2086
Hope this helps :)

3 0
2 years ago
A centipede has ______ legs
dezoksy [38]

100 legs. hope it helps!

7 0
3 years ago
Read 2 more answers
Simplify sqrt 244x + sqrt 36x - sqrt 25x
Morgarella [4.7K]
First simplify the square roots: 2 \sqrt{61x}+6 \sqrt{x}-5 \sqrt{x}
Then simplify the last two terms: 2 \sqrt{61x}+\sqrt{x}
Since 61 is prime, you can't take a rational root out of it. 
8 0
3 years ago
A figure has the following coordinates x (0,1).Y (4,6) z (-5,-1). If the figure is translates 4 units left and 3 units up, what
iVinArrow [24]

Answer:

z' (-9,2)

Step-by-step explanation:

I recomend using desmos to show the relashinship

If you don't want to, thwn do this

Preimage(0-4,1+3),(4-4,6+3),(-5-4,-1+3)

Since we are finding z, we only use the final cordinates

z'=(-9,2)

8 0
2 years ago
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