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ZanzabumX [31]
2 years ago
6

Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0).

Mathematics
1 answer:
hichkok12 [17]2 years ago
8 0

Answer:im not sure

Step-by-step explanation:

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You ride the subway about 45 times per month. should you buy the monthly pass
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Is it cheaper then without it? If so you should
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3 years ago
Help me pleaseeeeeeee​
nadya68 [22]
10^-8 because e-8 is 10^-8
8 0
3 years ago
The wind is blowing N 35.0 degrees W at 1.60 * 10^2 mph. A plane has an engine speed of 3.20 * 10^2 mph. Where should the pilot
andreyandreev [35.5K]

Answer: 24.2° SouthWest

<u>Step-by-step explanation:</u>

First step: DRAW A PICTURE of the vectors from head to tail <em>(see image)</em>

I created a perpendicular from the resultant vector to the vertex of the given vectors so I could use Pythagorean Theorem to find the length of the perpendicular. Then I used that value to find the angle of the plane.

<u>Perpendicular (x):</u>

 cos 35° = adjacent/hypotenuse

  cos 35° = x/160

→ x = 160 cos 35°

<u>Angle (θ):</u>

sin θ = opposite/hypotenuse

sin θ = x/320

sin θ = 160 cos 35°/320

    θ = arcsin (160 cos 35°/320)

    θ = 24.2°

Direction is down (south) and left (west)

7 0
3 years ago
Suppose x is a real number and epsilon &gt; 0. Prove that (x - epsilon, x epsilon) is a neighborhood of each of its members; in
kaheart [24]

Answer:

See proof below

Step-by-step explanation:

We will use properties of inequalities during the proof.

Let y\in (x-\epsilon,x+\epsilon). then we have that x-\epsilon. Hence, it makes sense to define the positive number delta as \delta=\min\{x+\epsilon-y,y-(x-\epsilon)\} (the inequality guarantees that these numbers are positive).

Intuitively, delta is the shortest distance from y to the endpoints of the interval. Now, we claim that (y-\delta,y+\delta)\subseteq  (x-\epsilon,x+\epsilon), and if we prove this, we are done. To prove it, let z\in (y-\delta,y+\delta), then y-\delta. First, \delta \leq y-(x-\epsilon) then -\delta \geq -y+x-\epsilon hence z>y-\delta \geq x-\epsilon

On the other hand, \delta \leq x+\epsilon-y then z hence z. Combining the inequalities, we have that  x-\epsilon, therefore (y-\delta,y+\delta)\subseteq  (x-\epsilon,x+\epsilon) as required.  

3 0
4 years ago
√6 + √30 <br><br> √36 + √36<br><br> √ - Square Root<br><br> Pls help :(
slavikrds [6]
The square root of 6 is 2.44 +
Square root of 30 is 5.47
So 2.44 + 5.47 is 4.01
Your answer is 4.01

Square root of 36 is 6
So 6+ 6 is 12
Your answer is 12


Hope this helps *smiles*
8 0
3 years ago
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