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Leya [2.2K]
2 years ago
13

A flash disk has the capacity of storing 1 megabyte of data. How many kilobytes of data can be stored in the same flash disk​

Mathematics
1 answer:
Luden [163]2 years ago
6 0

For this sort of problem, you need to be familiar with prefixes.

So:

megabyte = 1 *10^6 bytes

kilobyte = 1*10^3 bytes

and a regular byte would just be 1

Now, you will need to do a conversion:

1megabyte*\frac{1*10^6bytes}{1megabyte}*\frac{1*10^{-3}kilobyte}{1byte}

I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are 1*10^6 bytes!)

In the second fraction thought, remember one kilobyte is 1*10^3 bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do \frac{1kilobyte}{1*10^3bytes}, but I think it is more correct to do write it out how I did).

*** They do equal the same thing though! Do whichever way is easier for you!

Now, your answer should be:

10^3 kilobytes (1000 kilobytes)

Hope this helped!

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4 0
3 years ago
Find the volume of the following compound shape.<br>​
Bess [88]
<h3>Given:</h3>
  • Cone
  • Cylinder
<h3>Volume of the cone:</h3>

v =  \frac{1}{3} \pi {r}^{2} h

v =  \frac{1}{3}  \times \pi \times  {10}^{2}  \times 10

v = 1047.20 \:  {cm}^{3}

<h3>Volume of the cylinder:</h3>

v = \pi {r}^{2} h

v = \pi \times  {10}^{2}  \times 10

v = 3141.59 \:  {cm}^{3}

<h3>Total volume:</h3>

v = 1047.20 + 3141.59

v = 4188.79 \:  {cm}^{3}

<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>cone</u><u> </u><u>shape</u><u> </u><u>is</u><u> </u><u>4188.7</u><u>9</u><u> </u><u>cubic</u><u> </u><u>centimeters</u><u>.</u>

5 0
1 year ago
Read 2 more answers
Consider function f.
tekilochka [14]

Given:

The function is:

f(x)=\sqrt{7x-21}

To find:

The steps of finding the inverse function f^{-1}(x).

Solution:

We have,

f(x)=\sqrt{7x-21}

The steps of finding the inverse function are:

Step 1: Substitute f(x)=y.

y=\sqrt{7x-21}

Step 2: Interchange x and y.

x=\sqrt{7y-21}

Step 3: Taking square on both sides, we get

x^2=7y-21

Step 4: Adding 21 on both sides, we get

x^2+21=7y

Step 5: Divide both sides by 7.

\dfrac{1}{7}x^2+3=y

Step 6: Substitute y=f^{-1}(x).

\dfrac{1}{7}x^2+3=f^{-1}(x), where x\geq 0.

Therefore, the inverse of the given function is f^{-1}(x)=\dfrac{1}{7}x^2+3 and the arrangement of steps is shown above.

7 0
3 years ago
What are the solutions to the equation (2x – 5)(3x – 1) = 0?
user100 [1]

Answer: x=\frac{5}{2}, x=\frac{1}{3}

Explanation:

The equation is:

(2x-5)(3x-1)=0

The term on the left consists of a product of two different factors: therefore, this product can be zero if either the first term (2x-5) or the second term (3x-1) is equal to zero.

This means that we can solve separately for the two terms:

2x-5=0\\3x-1=0

Solving the first equation:

2x-5=0\\2x=5\\x=\frac{5}{2}

Solving the second equation:

3x-1=0\\3x=1\\x=\frac{1}{3}

8 0
2 years ago
Read 2 more answers
A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
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