Answer:
I think the answer is D. (2,6,8) because if the ones on the right are y - coordinates in the Function then it should be correct. If not sorry
(Range is y - coordinate)
(Domain is x - coordinate)
Find how much interest is earned for one year: $3000 x .015 = $45
Use that answer to find how much interest is earned for 15 years: $45 x 15 years = $675
Add original investment to interest for balance: $3000 + $675 = $3675
Yes
Reason - figure b has been increased by 3 (x3 for each side)
Eg. figure b - 1. Figure a - 3
<span>If you put the 9cm and 2cm rods together end-on-end, the new length is 11cm. Now if you repeat this with the 7cm and 5cm rods that new length is 12cm, so the difference between the two is now 1 cm. It does not seem very practical to walk around measuring items using the rods like this, so you could then make a small rod or use a strip of paper equal to the difference (1cm) as a standard measuring tool.</span>
The Babylonian method for approximating square roots is the recursive method given by:
Given:
x0≈k−−√
x
0
≈
k
Then:
xn+1=x2n+k2xn
x
n
+
1
=
x
n
2
+
k
2
x
n
where k
k
is the number for which we are approximating the square root.
So, armed with this formula, let's now answer the given questions:
1.) Fill in the missing info in the problem to find square root 130 by using the Babylonian method. Let 11.5 be your initial guess.
We will use 15 digits of precision here since it is not stated how many iterations to carry out:
x0=11.5
x
0
=
11.5
x1≈11.4021739130435
x
1
≈
11.4021739130435
x2≈11.4017542587143
x
2
≈
11.4017542587143
x3≈11.4017542509914
x
3
≈
11.4017542509914
x4≈11.4017542509914
x
4
≈
11.4017542509914
Thus, with 15 digits of accuracy, we may state:
130−−−√≈11.4017542509914
130
≈
11.4017542509914
2.) Use the Babylonian method for your next estimate of square root 115 by using 10.7262 as your guess what's your next result?
The next result here is approximately:
x1=10.72622+1152⋅10.7262≈10.7238055620816
x
1
=
10.7262
2
+
115
2
⋅
10.7262
≈
10.7238055620816
3.) Nails wants to use the Babylonia method to estimate square root 58 to the nearest hundredth her initial estimate is 7.8. What is her estimate after she correctly completes the Babylonian method once?
The next result here is:
x1=7.82+582⋅7.8=7.6179487¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
x
1
=
7.8
2
+
58
2
⋅
7.8
=
7.6
179487
¯
4.) If you use the Babylonian method to estimate square root 75 to the nearest hundredth, starting with the estimate 8. What is the next estimate?
The next result here is:
x1=82+752⋅8=8.6875
x
1
=
8
2
+
75
2
⋅
8
=
8.6875
