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Bingel [31]
3 years ago
15

Of the following, which is the solution to 2x2 − 5x = −8? the quantity negative five plus or minus i times the square root of th

irty nine over four the quantity five plus or minus i times the square root of thirty nine over four the quantity five plus or minus i times the square root of thirty nine over two the quantity negative five plus or minus i times the square root of one hundred ninety two over two
Mathematics
2 answers:
lutik1710 [3]3 years ago
5 0

Answer:

x=\frac{5+-\sqrt{39}}{4}

Step-by-step explanation:

find  the solution to 2x^2 -5x = -8

To solve the equation for x , we need to make right hand side 0

2x^2 -5x = -8, add 8 on both sides

2x^2 -5x+8 =0

Now use quadratic formula to solve for x

x=\frac{-b+-\sqrt{b^2-4ac} }{2a}

the value of a=2, b=-5 and c=8

Plug in all the values and solve for x

x=\frac{-b+-\sqrt{b^2-4ac} }{2a}

x=\frac{5+-\sqrt{(-5)^2-4(2)(8)} }{2(2)}

x=\frac{5+-\sqrt{39}}{4}

We cannot simplify more

aleksandrvk [35]3 years ago
4 0
2x²-5x+8=0
use the quadratic formula, x=(5+√39i)/4 of x=(5-√39i)/4
looks like the second choice is correct.
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Step-by-step explanation:

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What is pie minus 6 plus 50<br>​
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Answer:

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2 years ago
Use the limit definition of the derivative to find the slope of the tangent line to the curve
ale4655 [162]

Answer:

\displaystyle f'(4) = 63

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Distributive Property

<u>Algebra I</u>

  • Expand by FOIL (First Outside Inside Last)
  • Factoring
  • Function Notation
  • Terms/Coefficients

<u>Calculus</u>

Derivatives

The definition of a derivative is the slope of the tangent line.

Limit Definition of a Derivative: \displaystyle f'(x)= \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}  

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 7x² + 7x + 3

Slope of tangent line at x = 4

<u>Step 2: Differentiate</u>

  1. Substitute in function [Limit Definition of a Derivative]:                              \displaystyle f'(x)= \lim_{h \to 0} \frac{[7(x + h)^2 + 7(x + h) + 3]-(7x^2 + 7x + 3)}{h}
  2. [Limit - Fraction] Expand [FOIL]:                                                                    \displaystyle f'(x)= \lim_{h \to 0} \frac{[7(x^2 + 2xh + h^2) + 7(x + h) + 3]-(7x^2 + 7x + 3)}{h}
  3. [Limit - Fraction] Distribute:                                                                            \displaystyle f'(x)= \lim_{h \to 0} \frac{[7x^2 + 14xh + 7h^2 + 7x + 7h + 3] - 7x^2 - 7x - 3}{h}
  4. [Limit - Fraction] Combine like terms (x²):                                                     \displaystyle f'(x)= \lim_{h \to 0} \frac{14xh + 7h^2 + 7x + 7h + 3 - 7x - 3}{h}
  5. [Limit - Fraction] Combine like terms (x):                                                      \displaystyle f'(x)= \lim_{h \to 0} \frac{14xh + 7h^2 + 7h + 3 - 3}{h}
  6. [Limit - Fraction] Combine like terms:                                                           \displaystyle f'(x)= \lim_{h \to 0} \frac{14xh + 7h^2 + 7h}{h}
  7. [Limit - Fraction] Factor:                                                                                 \displaystyle f'(x)= \lim_{h \to 0} \frac{h(14x + 7h + 7)}{h}
  8. [Limit - Fraction] Simplify:                                                                               \displaystyle f'(x)= \lim_{h \to 0} 14x + 7h + 7
  9. [Limit] Evaluate:                                                                                                 \displaystyle f'(x) = 14x + 7

<u>Step 3: Find Slope</u>

  1. Substitute in <em>x</em>:                                                                                                \displaystyle f'(4) = 14(4) + 7
  2. Multiply:                                                                                                           \displaystyle f'(4) = 56 + 7
  3. Add:                                                                                                                  \displaystyle f'(4) = 63

This means that the slope of the tangent line at x = 4 is equal to 63.

Hope this helps!

Topic: Calculus AB/1

Unit: Chapter 2 - Definition of a Derivative

(College Calculus 10e)

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Step-by-step explanation:

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