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Elena-2011 [213]
2 years ago
11

The graph below shows the speed of a car that is driven through a town and then on a major highway. During which of the followin

g time intervals was the car stopped at a traffic light?

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
4 0

Considering the graph of the velocity of the car, it is found that the interval in which it was stopped at a traffic light was:

Between 3 and 4 minutes.

<h3>When is a car stopped at a traffic light?</h3>

When a car is stopped at a traffic light, the car is not moving, that is, it's velocity is of zero.

In this problem, the graph gives the <u>velocity as a function of time</u>, and it is at zero between 3 and 4 minutes, hence the interval in which it was stopped at a traffic light was:

Between 3 and 4 minutes.

More can be learned about the interpretation of the graph of a function at brainly.com/question/3939432

#SPJ1

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Answer:

2

Step-by-step explanation:

\frac{-8(17-12)}{-2(8-(-2))} \\=\frac{-8(5)}{-2(8+2)} \\=\frac{-40}{-2(10)} \\=\frac{-40}{-20} \\=2

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3 years ago
How many complex and real roots are in the problem (x+10)^9.
Katena32 [7]

Answer:

9 roots

Step-by-step explanation:

(x+10)^9 = 0

If you would multiply it out, the highest power is x^9 so the equation has 9 roots

Solving (x+10)^9 =0

Taking the 9th root of each sdie

x+10 = 0

x = -10

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5) n * n * n * n * 6 * 6 * 6

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4 0
3 years ago
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Please help ASAP.. Question below
Ugo [173]

Answer:

option B and option D

0 and 2

Step-by-step explanation:

Given in the question two functions

f(x) = x² - 4x + 3

g(x) = -x² + 3

f(x) = g(x)

x² - 4x + 3 = - x² + 3

Rearrange the like terms, x terms to the left and constant term to the right.

x²+ x² - 4x = 3 - 3

2x² - 4x = 0

Divide by two

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Take x as a common term

x(x-2) = 0

so

x = 0

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8 0
4 years ago
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Which equation has exactly two real and two non real solutions?
tatiyna

Answer:

The first option x^4-21x^2-100=0.

Step-by-step explanation:

To have exactly 2 real and two non real solutions, the degree of the polynomial must be a degree 4. Degree is the highest exponent value in the polynomial and is also the number of solutions to the polynomial. This polynomial ha 2 real+2 non real= 4 solutions and must be x^4. This eliminates the bottom two solutions.

In order to have two real and two non real solutions, the polynomial must factor. If it factors all the way like

x^4-100x^2=0\\x^2(x^2-100)=0\\x^2(x-10)(x+10)=0\\\\x^2=0\\x-10=0\\x+10=0

This means x=0, 10, -10 are real solutions to the polynomial. It has no non real solutions. This eliminates this answer choice.

Only answer choice 1 meets the requirement.

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4 years ago
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