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Vedmedyk [2.9K]
2 years ago
7

Select all that are measures of angles that are coterminal with a –50° angle.

Mathematics
1 answer:
artcher [175]2 years ago
7 0

The expression θ = - 50° ± i · 360°, i \in \mathbb{N}_{O} represents the family of all angles <em>coterminal</em> with - 50° angle.

<h3>What is the family of angles coterminal to a given one?</h3>

Two angles are <em>coterminal</em> if and only if their end have the <em>same</em> direction. Two <em>consecutive coterminal</em> angles have a difference of 360°. Then, we can derive an expression representing the family of all angles <em>coterminal</em> to - 50° angle.

θ = - 50° ± i · 360°, i \in \mathbb{N}_{O}

The expression θ = - 50° ± i · 360°, i \in \mathbb{N}_{O} represents the family of all angles <em>coterminal</em> with - 50° angle.

<h3>Remark</h3>

The statement is incomplete and complete form cannot be reconstructed. Thus, we modify the statement to determine the family of angles coterminal to - 50° angle.

To learn more on coterminal angles: brainly.com/question/23093580

#SPJ1

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<span>The volume of a rectangular prism is:</span>

V=l*w*h<span>
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Where

l=lenght,

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So, as this prism has a length of 312 inches, a width of 5 inches, and a height of 112 inches, the volume is calculated as follows:

V=l*w*h=312 in*5 in*112 in=174 720 inches^3

 

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Potassium helps the human body prevent muscle cramping. Researchers sampled 52 random professional wrestlers. The average potass
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Answer:

D. The 95% confidence interval is (3.4102, 4.1898). We are 95% confident that the true population mean potassium level for professional wrestlers will be between 3.4102 millimoles per liter and 4.1898 millimoles per liter.

Step-by-step explanation:

Hello!

The variable if interest is X: potassium level of a professional wrestler  (mmol/L)

A sample of n= 52 professional wrestlers was taken and a sample mean of X[bar]= 3.8 mmol/L and a sample standard deviation of S= 1.4 mmol/L

You have to estimate the population average potassium level using a 95% confidence interval. Assuming that the variable has a normal distribution, and since the population variance is unknown, I'll use a student t to construct the interval:

[X[bar] ± t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }]

t_{n-1;1-\alpha /2}= t_{51;0.975}= 2.008

[3.8±2.008*\frac{1.4}{\sqrt{52} }]

[3.4102; 4.1898]

With a 95% confidence level you'd expect that the interval [3.4102; 4.1898]mmol/L will contain the average potassium level of professional wrestlers.

I hope this helps!

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