Select all that are measures of angles that are coterminal with a –50° angle.

1 answer:

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The expression θ = - 50° ± i · 360°, $i \in \mathbb{N}_{O}$ represents the family of all angles <em>coterminal</em> with - 50° angle.

<h3>What is the family of angles coterminal to a given one?</h3>

Two angles are <em>coterminal</em> if and only if their end have the <em>same</em> direction. Two <em>consecutive coterminal</em> angles have a difference of 360°. Then, we can derive an expression representing the family of all angles <em>coterminal</em> to - 50° angle.

θ = - 50° ± i · 360°, $i \in \mathbb{N}_{O}$

The expression θ = - 50° ± i · 360°, $i \in \mathbb{N}_{O}$ represents the family of all angles <em>coterminal</em> with - 50° angle.

<h3>Remark</h3>

The statement is incomplete and complete form cannot be reconstructed. Thus, we modify the statement to determine the family of angles coterminal to - 50° angle.

To learn more on coterminal angles: brainly.com/question/23093580

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What are the coordinates of the y-intercept of the line who's equation is 12x + 13y =8???

Ierofanga [76]

Answer:

y-intercept = (0, $\frac{8}{13}$ ).

Step-by-step explanation:

Given the linear equation in standard form, 12x + 13y = 8:

We must transform this equation into slope-intercept form to make it easier to determine the coordinates of the y-intercept.

12x + 13y = 8

Subtract 12x from both sides:

12x + 13y - 12x = - 12x + 8

13y = - 12x + 8

Next, divide both sides of the equation by 13 to solve for y:

$\frac{13y}{13} = \frac{-12x + 8}{13}$

$y = \frac{-12x + 8}{13}$ or $y = -\frac{12}{13} x + \frac{8}{13}$

Next, to determine the y-intercept, we must set x = 0 (because the y-intercept is the point where the graph of the linear equation crosses the y-axis).

Let x = 0:

$y = -\frac{12}{13} x + \frac{8}{13}$

$y = -\frac{12}{13} (0) + \frac{8}{13}$