Semi monthly means 2 times per month
assume that pay is at beginning and middle of month (doesn't matter, but makes it easier for me)
so 12 months
2 times per month
12 times 2=24
divide 55000 by number of months
55,000/24=2291.67
so the amount per paycheck, assuming equally distributed amounts throughout the paychecks, is $2291.67
The given function are
r(x) = 2 - x² and w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
= 2x - x³ - 4 + 2x²
∴ <span>
(w*r)(x) = -x³ + 2x² + 2x - 4</span>
<span>It is a polynomial function with a domain equal to R
</span>
The range of <span>(w*r)(x) can be obtained by graphing the function
</span>
To graph (w*r)(x), we need to make a table between x and (w*r)(x)
See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>
As shown in the graph the range of <span>
(w*r)(x) is (-∞,∞)</span>
Lets x = width
length = x + 4 (4 meters longer than wide)
A = L * W
192 = x ( x +4)
192 = x^2 + 4x
x^2 + 4x - 192 = 0
(x +16)(x-12) = 0
x - 12 = 0, x = 12
x + 16 = 0, x = -16
so width x = 12
length = 12 + 4 = 16 (4 meters longer than wide)
answer. J
16
Answer:
x = -7
Solution:
4(1-x) + 2x = -3( x + 1)
4(1 - x) + 2x = -3 (x + 1)
4(-x + 1) + 2x = -3 (x + 1)
-4x - 4 + 2x = -3(x + 1)
-2x + 4 = -3 (x + 1)
Answer:
Step-by-step explanation:
Gotta love these motion problems!!! This one is especially tricky! At noon, ship A is 180 km west of ship B. If ship A is traveling east, it is closing its distance to ship B (if ship B didn't move). But ship B is moving north at the same time. We need to find the distance each can travel in 4 hours using the d = rt formula. For ship A. We know it's moving at 35 km/h, so in 4 hours it can move d = 35(4) which is 140 km. Remember that is closing the distance to ship B. So it is 180 - 140 directly south of ship B. This problem will turn out to be a right triangle problem of sorts. The distance of 40 km serves as the base of this right triangle.
With ship B moving north at 25 km/hr, it can travel d = 25(4) which is 100 km. This serves as the height of the triangle. We are asked to find the rate at which the distance is changing 4 hours from their starting points. We know how far each can travel in those 4 hours, so in order to find the rate of change (which is the same thing as the slope!), we take the height and divide it by the base because that is the same thing as taking the rise over the run. 100/40 is 10/4 which is a rate of change of 2.5 km/hr