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1 year ago

Help I'm confused with this question

Mathematics

2 answers:

ad-work [718]1 year ago

8 0

The numerical pattern counts by 11 each time the personal ID numbers increase. 2 + 11 = 13, 13 + 11 = 24, 24 + 11 = 35. To find the next ID numbers, what we can do is add eleven to the result we get.

Since 35 + 11 = 46, 46 is our next number in the ID.

Since 46 + 11 = 57, 57 is our next number in the ID.

Since 57 + 11 = 68, 68 is our next number in the ID.

Your final answer: In the first blank, we added by 11 and got 46. In the second blank, we added by 11 and got 57. In the third blank, we added by 11 and got 68. Combining these numbers with all of the other numbers, the ID of one customer would be 2132435465768. If you need extra help, let me know and I will gladly assist you.

alukav5142 [94]1 year ago

4 0

The pattern is going up by elevens each time. So basically you take the second number(A2) and subtract it from the first number(A1).
so short answer is: 46, 57, 68

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A new centrifugal pump is being considered for an application involving the pumping of ammonia. The specification is that the fl

cricket20 [7]

Answer:

1) We need to conduct a hypothesis in order to check if the true mean is higher than 5 gpm, the system of hypothesis would be:

Null hypothesis: $\mu \leq 5$

Alternative hypothesis: $\mu > 5$

2) $df=n-1=8-1=7$

Since is a one sided test the p value would be:

$p_v =P(t_{(7)}>2.233)=0.0304$

3) For this case is we use a significance level of 1% or 99% of confidencewe see that $p_v >\alpha$ and we don't have enough evidence to conclude that the specification is satified. But if we use a value of significance $\alpha=0.05$ or 95% of confidence we see that $p_v$ and we have enough evidence to conclude that the specification is satisfied.

Step-by-step explanation:

Data given and notation

$\bar X=6.5$ represent the sample mean

$s=1.9$ represent the sample standard deviation

$n=8$ sample size

$\mu_o =5$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part 1: State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is higher than 5 gpm, the system of hypothesis would be:

Null hypothesis: $\mu \leq 5$

Alternative hypothesis: $\mu > 5$

If we analyze the size for the sample is <30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{6.5-5}{\frac{1.9}{\sqrt{8}}}=2.233$

Part 2: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=8-1=7$

Since is a one sided test the p value would be:

$p_v =P(t_{(7)}>2.233)=0.0304$

Part d: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the height of men actually its significant higher compared to the height of men in 1960 at 1% of signficance.

Part 3

For this case is we use a significance level of 1% or 99% of confidencewe see that $p_v >\alpha$ and we don't have enough evidence to conclude that the specification is satified. But if we use a value of significance $\alpha=0.05$ or 95% of confidence we see that $p_v$ and we have enough evidence to conclude that the specification is satisfied.

4 0

2 years ago

Is y-4=2(x-2) and 4x-2y=5 perpendicular

djyliett [7]

Answer:

Therefore,

Slopes are Equal, Hence the Lines are not Perpendicular.

Step-by-step explanation:

Given:

$y-4=2(x-2)=2x=-4\\\\y=2x$ .......Equation ( 1 )

$4x-2y=5\\2y=4x-5\\\\y=2x-\dfrac{5}{2}$ .......Equation ( 2 )

Comparing with,

$y=mx+c$ ......General Slope point form

Where m =slope

We get

$Slope = m1 = 2$ For Equation ( 1 )

$Slope = m2 = 2$ For Equation ( 2 )

Hence,

$m1=m2[=2$

Therefore, Slopes are Equal Hence the Lines are Parallel not Perpendicular.

For Perpendicular we require

$m1\times m2=-1$

Therefore,

Slopes are Equal, Hence the Lines are not Perpendicular.

7 0

2 years ago

NEED THIS ASAP Write the equation of a circle with a center at (1, 4) where a point on the circle is (4, 8).

AlekseyPX

Answer:

(x-1)^2 + (y-4)^2 = 5^2

Step-by-step explanation:

Using the standard equation of a circle with center at (h, k) and radius r:

(x-h)^2 + (y-k)^2 = r^2, we substitute 1 for h, 4 for k, 4 for x and 8 for y:

(4-1)^2 + (8-4)^2 = r^2, or

9 + 16 = 25 = r^2

Thus, the radius is 5

and the equation is (x-1)^2 + (y-4)^2 = 5^2. This matches the 2nd answer choice.

5 0

2 years ago

kipiarov [429]

Answer:

Jumper, y = 172

Shirt, x = - 105

Step-by-step explanation:

Let :

Shirt = x

Jumper = y

5x + 4y = 163 - - (1)

3x + 2y = 29 - - - (2)

Multiply (1) by 3 and (2) by 5

15x + 12y = 489 - - - (3)

15x + 10y = 145 - - - (4)

Subtract :

12y - 10y = 489 - 145

2y = 344

y = 344 / 2

y = 172

Put y = 172 in (3)

15x + 12(172) = 489

15x + 2064 = 489

15x = 489 - 2064

15x = - 1575

x = - 105

The values ;

Jumper, y = 172

Shirt, x = - 105

We weren't supposed to obtain a negative value, kindly check if the parameters given are correct.

5 0

3 years ago

Help help help pls pls pls

alex41 [277]

Answer: 14.48000 . . . ≤ t < 15.0000

Step-by-step explanation:

"Truncated by a hundreths of a second" means that the time was rounded to the nearest 0.0X second. That would mean the reported time of 14.48 seconds was shortened from a time period having more digits to the right. For example, If the time were actually 14.48223 seconds, the time was truncated to just 14.48 seconds. The term used here. truncated, means that the digits after the hunredth place are simply dropped. It doesn't say rounded, just truncated. Brutal. So that would mean that times between 14.48000 . . . and 14.48999 . . . would all be reported as 14.48 seconds.

So the time could actually be 14.48000 . . . ≤ t < 15.0000

3 0

2 years ago

Help I'm confused with this question​

Help I'm confused with this question