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RSB [31]
1 year ago
9

Anabelle collected data on the favorite superhero of the students in her class. The table shows the relative frequencies of rows

for the data collected: Favorite Superhero Superman Spiderman Batman Wonder Woman Row totals Boys 0.21 0.25 0.06 0.11 0.63 Girls 0.25 0.02 0.03 0.07 0.37 Column totals 0.46 0.27 0.09 0.18 1 Based on the data, which superhero is most likely to be the favorite
Mathematics
1 answer:
valentinak56 [21]1 year ago
8 0

Considering the proportions given in the table, the superhero is most likely to be the favorite is Superman.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

Looking at the table, the proportions associated with each superhero is given as follows:

  • Superman: 0.46.
  • Spiderman: 0.27.
  • Batman: 0.09.
  • Wonder woman: 0.18.

As it has the highest proportion, the superhero is most likely to be the favorite is Superman.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

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your job pays 8$ per hour Write a variable expression for your pay in dollars for working h hours. What is your pay if you work
lawyer [7]

Answer:

$8h

Your pay is $288 for working 36 hours

Step-by-step explanation:

I hope this helps :)

7 0
3 years ago
For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains
AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

f(x) = (1-p)^{x}p

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

\mu = \frac{1-p}{p}

The standard deviation of the geometric distribution is given by the following formula:

\sigma = \sqrt{\frac{1-p}{p^{2}}

In this problem, we have that:

p = 0.383

So

\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61

\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05

(a) What is the probability that a drought lasts exactly 3 intervals?

This is f(3)

f(x) = (1-p)^{x}p

f(3) = (1-0.383)^{3}*(0.383)

f(3) = 0.09

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is P = f(0) + f(1) + f(2) + f(3)

f(x) = (1-p)^{x}p

f(0) = (1-0.383)^{0}*(0.383) = 0.383

f(1) = (1-0.383)^{1}*(0.383) = 0.236

f(2) = (1-0.383)^{2}*(0.383) = 0.146

Previously in this exercise, we found that f(3) = 0.09

So

P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4).

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

P(X \leq 3) + P(X \geq 4) = 1

0.855 + P(X \geq 4) = 1

P(X \geq 4) = 0.145

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0
3 years ago
What is the square root of 50?
notka56 [123]

Answer:

√50= 5√2

Step-by-step explanation:

50=25*2

√50=√25*2

√50=√5*5*2

√50= 5√2

3 0
3 years ago
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kherson [118]
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3 years ago
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Alchen [17]

Answer:

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Step-by-step explanation:

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L = 21, W = 2 giving perimeter = 46 ft.

3 0
3 years ago
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