Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
Answer:
1/2, or 0.5
Step-by-step explanation:
There are 4 ways that 2 coins can fall...
Both heads (this satisfies our situation)
1st coin heads, 2nd coin tails
1st coin tails, 2nd coin heads
Both tails (this satisfies our situation)
We have 2 out of 4 ways to satisfy this situation, so our experimental probability is
P = 2/4 which reduces to
P = 1/2 , or 0.5 as a decimal
Line b and h because to find radius it half of the diameter of STRAIGHT lines
Answer:
Step-by-step explanation:
we know that
In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference (d)
In this problem we have the ordered pairs
Let
Find the difference between one term and the next
The difference between one term and the next is a constant
This constant is the common difference
so
The sequence graphed is an Arithmetic Sequence
therefore
The first term is
The common difference is equal to
