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Dafna1 [17]
2 years ago
11

Determine oxidation states and answer the following questions about the reaction 2Li 2H2O 2LiOH H2. (1 point)

SAT
1 answer:
Luden [163]2 years ago
4 0

The oxidation state of Lithium changed from 0 to +1

The oxidation state of hydrogen changed from +1 to 0.

<h3>What is the oxidation state of the elements in the reaction?</h3>

The equation of the redox reaction is given as follows:

2 Li + 2 H₂O → 2 LiOH + H₂

The oxidation states of the elements changed as follows:

The oxidation state of Lithium changed from 0 to +1

The oxidation state of hydrogen changed from +1 to 0.

In conclusion, the reaction is a redox reaction.

Learn more about oxidation state at: brainly.com/question/27239694

#SPJ1

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Factor the expression into an equivalent form 12y^2-75.
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Hello oddworld7836!

\huge \boxed{\mathbb{QUESTION} \downarrow}

Factor the expression into an equivalent form 12y² - 75.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

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By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.

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__________________

Hope it'll help you!

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