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svlad2 [7]
2 years ago
15

I’m really confused on this problem., pls help me!

Mathematics
2 answers:
777dan777 [17]2 years ago
8 0

Answer:

Domain: All Real Numbers

Range: All Real Numbers

Step-by-step explanation:

So the domain of a function can be defined as an interval of x-values, which you can input into the function and get real numbers as an output. Since we have a cube root here, or more specifically an odd nth root, the domain is all real numbers, since cbrt(negative number) will just be a negative number since (negative number * negative number * negative number) = negative number, so there does exist a solution, unlike even nth roots like square root, which is restricted to only positive values inside the radical, otherwise you get non-real solutions.

Now let's look at the range of the function, which can be defined as an interval of y-values which can possibly be outputted by the function.

Since as mentioned before, the cube root isn't limited to a certain interval, and rather all real numbers, the range is also similar, since whenever you have a negative number in the radical, the output will be a negative number, so the range is all real numbers

Damm [24]2 years ago
8 0

The answer is A.

As any number can be inputted in place of x and the result, y, will be directly proportional to the inputting value, the domain and range of the function is All Real Numbers.

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12(x−2)+3x=x+12+10x

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