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lorasvet [3.4K]
3 years ago
5

In Melissa's new clothing store, she charges $19.25 for each shirt she sells.

Mathematics
2 answers:
kiruha [24]3 years ago
4 0

Answer:904.75

Step-by-step explanation:

viva [34]3 years ago
3 0

19.25*47=$904.75

i hope this is what your looking for

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What is the measure of angles g
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C.) 28

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its flat angles long the bottom line cause it to be equal

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Twenty four is less than 10 times the number equals 64 more than 8 times a number.
Elena-2011 [213]
You would write the equation like this:
24-10n=64+8n
3 0
3 years ago
F(x)= x2<br> What is f(x) + f(x) + f(x)?
Irina18 [472]

Answer:

Step-by-step explanation:

You already have f(x)= x2

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3(2x)=6x

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3 years ago
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A right square pyramid is shown. The height of the pyramid is 6 units. The distance from the center of the base of the pyramid t
elena-14-01-66 [18.8K]

Answer:

<em>AD is 6.5 units</em>

Step-by-step explanation:

Find the diagram attached.

From the diagram, you can see that the dotted triangle is a right angled triangle with side AD as the hypotenuse.

To get AD, we will use the pythagoras theorem as shown;

Hyp² = Opp² + Adj²

AD² = 6²+2.5²

AD² = 36 + 6.25

AD² = 42.25

AD = √42.25

<em>AD = 6.5</em>

<em>Hence the measure of length segment AD is 6.5 units</em>

6 0
3 years ago
ALGEBRA QUESTION PLS HELPS
cluponka [151]

The value of x is –7.

Solution:

Given expression:

$\left(\frac{1}{x+3}+\frac{6}{x^{2}+4 x+3}\right) \cdot \frac{x+3}{x+1}

Let us factor x^2+4x+3.

x^2+4x+3=(x+1)(x+3)

Substitute this in the fraction.

$\left(\frac{1}{x+3}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

To make the denominator same, multiply and divide the first term by (x +1).

$\left(\frac{(x+1)}{(x+1)(x+3)}+\frac{6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

Denominators are same, you can add the fractions.

$\left(\frac{x+1+6}{(x+1)(x+3)}\right) \cdot \frac{x+3}{x+1}

$\frac{x+7}{(x+1)(x+3)} \cdot \frac{x+3}{x+1}

Cancel the common term in the numerator and denominator.

$\frac{x+7}{x+1} \cdot \frac{1}{x+1}

Multiply the fractions.

$\frac{x+7}{(x+1)^2}

$\frac{x+7}{x^2+2x+1}

The expression is simplified to one rational expression.

Suppose the expression is equal to 0.

$\frac{x+7}{x^2+2x+1}=0

Do cross multiplication.

${x+7}=0\times (}{x^2+2x+1})

Any number or variable multiplied by 0 gives 0.

${x+7}=0

Subtract 7 from both sides of the equation.

${x+7-7}=0-7

x = –7

The value of x is –7.

7 0
3 years ago
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