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lutik1710 [3]
2 years ago
14

Find the equation of the line passing through the points (3,7) and (-2,5)

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
7 0

Answer:

The equation of the line passing through the points (3,7) and (-2,5) is y=⅖x+29/5

Step-by-step explanation:

Greetings !

first \: find \: the \: slope \: m \\ m =  \frac{(Y₂-Y₁)}{(X₂-X₁)} ..substitute \: vlues \\ m =  \frac{(5 - 7)}{( - 2 - 3)}  =  \frac{ - 2}{ - 5}  =  \frac{2}{5}  \\ y = mx + b \: to \: find \: equation \: of \: aline \\ between \: two \: poins and \: use \:  \\ one \: of \: the \: two \: points \: lets \: take( - 2.5) \\ y = mx + b \\ 5 =  \frac{ - 2}{5} ( - 2) + b \\ 5 =  \frac{ - 4}{5}  + b \\ 5 +  { - 4}^{5}  = b \\  \frac{25 + 4}{5}  = b \\ b =  \frac{29}{5}  \\ finally \: equation \: of \: the \: line \: will \: be \\ y =  \frac{2}{5} x +  \frac{29}{5}

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