To solve this you can use subtraction
186-27=159 (for the amount Eric gave away)
So Eric has 159 stars left!
Hope this helped!!
Answer:
23 chalkboards
Step-by-step explanation:
Given:
Mean length = 5 m
Standard deviation = 0.01
Number of units ordered = 1000
Now,
The z factor =
or
The z factor =
or
Z = - 2
Now, the Probability P( length < 4.98 )
Also, From z table the p-value = 0.0228
therefore,
P( length < 4.98 ) = 0.0228
Hence, out of 1000 chalkboard ordered (0.0228 × 1000) = 23 chalkboard are likely to have lengths of under 4.98 m.
X = -2 and y = -6. your welcome :)
we have

Solve for c--------> that means that clear variable c
so
Divide by
both sides

Adds
both sides

Multiply by
both sides
![a[(R/5)+0.3]=c](https://tex.z-dn.net/?f=a%5B%28R%2F5%29%2B0.3%5D%3Dc)
so
![c=a[(R/5)+0.3]](https://tex.z-dn.net/?f=c%3Da%5B%28R%2F5%29%2B0.3%5D)
therefore
<u>the answer is</u>
![c=a[(R/5)+0.3]](https://tex.z-dn.net/?f=c%3Da%5B%28R%2F5%29%2B0.3%5D)