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3 years ago

Find an equation in slope-intercept form for the line with slope 5 and y-intercept = -2

1 answer:

4 0

General form of slope-intercept equation
y = mx + b

The equation can be calculated using formula
y - y₁ = m(x - x₁)

From the question, we know that
m = 5
the y-intercept have 0 as the x-coordinate, so
(x₁,y₁) = (0,-2)

Make the equation
y - y₁ = m(x - x₁)
y - (-2) = 5(x - 0)
y + 2 = 5x
y = 5x - 2

The answer is c

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The length of a rectangular garden is three feet less than twice it’s width. If the perimeter of the garden is 42 feet, what is

Masja [62]

Answer:

The length of a rectangular garden is: 13 feet

Step-by-step explanation:

You have 2 lengths that are 2x-3 feet, and 2 widths that are x.

2x-3 + 2x-3 +x +x =42 feet

4x -6 +2x -42 feet

6x -6 = 42 feet

6x = 48 feet

x = 8 feet (so, 2x-3 = 16-3 = 13 feet)

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3 years ago

Sally's soccer team played 40 games and won 17 of them. What percent of the games did the team win

Kobotan [32]

Answer:

42.5%

Step-by-step explanation:

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3 years ago

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A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to

Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

= $2\pi r$

$=(2\times 3.14 \times 32) ft$

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

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4 years ago

I need help plzzzz I don't know how to

Assoli18 [71]

it would be 48 because you would multiply 8 and 12 but then divide by 2

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3 years ago

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Let f be a differentiable function such that f(3)=15, f(6)=3, f ' (3)= -8, and f ' (6)= -2. The function g is differentiable and

Ray Of Light [21]

Answer:

A. $g'(3)=-\frac{1}{2}$

Step-by-step explanation:

We have been given that f be a differentiable function such that $f(3)=15$ , $f(6)=3$ , $f'(3)= -8$ , and $f'(6)= -2$ . The function g is differentiable and $g(x)= f^{-1} (x)$ for all x.