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Elis [28]
2 years ago
11

Simplify the expression 4x^3/28x^4

Mathematics
1 answer:
KIM [24]2 years ago
5 0
1/7x

Factorize the numbers (4 and 28) as they have a common factor of 4 so you can simplify it to 1/7. Cancel out the 3 in the x (numerator) from the denominator and you will have x^1 remaining in the denominator. That is also the same as x, therefore making it 1/(7x)
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Step-by-step explanation:

maybe that is the data where those born in that year are placed

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Which of the following formulas could be used to find the area, A, of a triangle with base b and height h?
Artist 52 [7]
The correct formula to use when finding the area of this triangle is A= 1/2(b)(h). Hope this helps.
5 0
3 years ago
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NEED HELP ASAP
Aliun [14]
Well, first you want to figure out how many sentences Jolie has left to read. You can do that by multiplying 120 by 17 which equals 2,040. Then you have to divide 2,040 by 14. The answer to that is about 145.72 which you could just leave at about 145 minutes. And to simplify that even more you could divide by 60 and figure that 145.72 is about 2 hours and 42 minutes.
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3 years ago
A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha
White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

\frac{dB}{dt} = rB-k

\Rightarrow \frac{dB}{dt} - rB=-k.......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor =e^{\int p(t) dt

                                     =e^{\int (-r)dt

                                     =e^{-rt}

Multiplying the integrating factor the both sides of equation (1)

e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}

\Rightarrow  e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt

Integrating both sides

\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt

\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C        [ where C arbitrary constant]

\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}

Initial condition B=7864 when t =0

\therefore 7864= \frac{k}{r} - Ce^0

\Rightarrow  C= \frac{k}{r} -7864

Then the general solution is

B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}

\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

                                                 =$1573.17

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The area is 40 units
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