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Ivenika [448]
3 years ago
15

Graph the function y = |1.6x – 2| – 3.2. Over which interval is the function increasing?

Mathematics
2 answers:
BARSIC [14]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Trust me it is correct. Once you graph it all out it'll make sense

Murrr4er [49]3 years ago
3 0
Hmm,
the absolute value makes whaterver inside positive
so

find whre the abslte value is 0
1.6x-2=0
1.6x=2
x=2/1.6
x=1.25

as x approaches 1.25, the function decreases

so from left to right
from the left to right, from -ifninty to 1.25, it is decreasing
from 1.25 to infinity, it is increasing

so it is increasing in the interval (1.25,∞)
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What is the standard form of (6x^2-8x-7)+(8x^2-76x)
Studentka2010 [4]

Answer:  14x^2 - 84x - 7

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Explanation:

The like terms 6x^2 and 8x^2 combine to 14x^2

The like terms -8x and -76x combine to -84x

Nothing pairs with the -7, so its stays as is.

Standard form is where we list the terms in decreasing exponent order. We can think of -84x as -84x^1 and the -7 as -7x^0. So 14x^2 - 84x - 7 would be the same as 14x^2 - 84x^1 - 7x^0. The exponents count down: 2,1,0.

The final answer is a trinomial since it has three terms. It is also a quadratic because the degree (highest exponent) is 2.

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3 years ago
Which of the following shapes describes the 2d figure formed by slicing parallel to the base of a triangular prism
Arte-miy333 [17]

Answer:

c. square.

Step-by-step explanation:

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7 0
3 years ago
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The distribution of heights for adult men in a certain population is approximately normal with mean 70 inches and standard devia
KengaRu [80]

Answer:

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12]

Step-by-step explanation:

I beleive those options corresponds to another question, i will ignore them. We want to know an interval in which the probability that a height falls there is 0.8.

In such interval, the probability that a value is higher than the right end of the interval is (1-0.8)/2 = 0.1

If X is the distribuition of heights, then we want z such that P(X > z) = 0.1. We will take W, the standarization of X, wth distribution N(0,1)

W = \frac{X-\mu}{\sigma} = \frac{X-70}{4}

The values of the cumulative distribution function of W, denoted by \phi , can be found in the attached file. Lets call y = \frac{z-70}{4} . We have

0.1 = P(X > z) = P(\frac{X-70}{4} > \frac{z-70}{4}) = P(W > y) = 1-\phi(y)

Thus

\phi(y) = 1-0.1 = 0.9

by looking at the table, we find that y = 1.28, therefore

\frac{z-70}{4} = 1.28\\z = 1.28*4+70 = 75.12

The other end of the interval is the symmetrical of 75.12 respect to 70, hence it is 70- (75.12-70) = 64.88.

The interval (meassured in Inches) that represent the middle 80% of the heights is [64.88, 75.12] .

Download pdf
8 0
3 years ago
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