Let x represent the side length of the square end, and let d represent the dimension that is the sum of length and girth. Then the volume V is given by
V = x²(d -4x)
Volume will be maximized when the derivative of V is zero.
dV/dx = 0 = -12x² +2dx
0 = -2x(6x -d)
This has solutions
x = 0, x = d/6
a) The largest possible volume is
(d/6)²(d -4d/6) = 2(d/6)³
= 2(108 in/6)³ = 11,664 in³
b) The dimensions of the package with largest volume are
d/6 = 18 inches square by
d -4d/6 = d/3 = 36 inches long
Answer:
f(2) = 0 and f(6) = -4
Step-by-step explanation:
First, find f(x) when x = 2
Plug in 2 as x in the function:
f(x) = -(x - 2)
f(2) = -(2 - 2)
f(2) = -(0)
f(2) = 0
Next, find f(x) when x = 6. Plug in 6 as x in the function:
f(x) = -(x - 2)
f(6) = -(6 - 2)
f(6) = -(4)
f(6) = -4
So, f(2) = 0 and f(6) = -4
The answer to your question is 8.6
Answer:
<h2>2. D. 64</h2><h2>5. B. 1, -3/2</h2><h2>6. C. 0, 2</h2>
Step-by-step explanation:


