A bag contains 1 white (W), 3 blue (B1, B2, B3), and 2 red (R1, R2) marbles. (4 points)
1 answer:
The possible outcomes are WH, BH, BH, BH, RH, RH, WL, BL, BL, BL, RL, RL
<h3>How to determine the possible outcomes?</h3>The given parameters are:
Coin = Head (H) and Tail (T)
Marble = W, B, B, B, R, R
See attachment for the tree diagram
From the tree diagram, we have the following possible outcomes
WH, BH, BH, BH, RH, RH, WL, BL, BL, BL, RL, RL
Read more about tree diagram at:
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By summing the areas of <em>minor</em> rectangles and triangles, the area of the <em>irregular</em> polygon whose vertices are (- 3, 4), (2, 4), (4, 2), (2, - 3) and (- 3, - 3) is equal to 42 square units.
<h3>How to determine the area of a irregular polygon</h3>
In this problem we have to determine the area of a <em>irregular</em> polygon, whose calculation is defined as a sum of the areas of triangles and rectangles. To determine the combination of squares and triangles, we need first to plot the vertices and construct the figure on a <em>Cartesian</em> plane.
The area of the irregular figure is:
A = (5) · (7) + 0.5 · 2² + 0.5 · (2) · (5)
A = 35 + 2 + 5
A = 42
By summing the areas of <em>minor</em> rectangles and triangles, the area of the <em>irregular</em> polygon whose vertices are (- 3, 4), (2, 4), (4, 2), (2, - 3) and (- 3, - 3) is equal to 42 square units.
To know more on polygons: brainly.com/question/10441863
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