A bag contains 1 white (W), 3 blue (B1, B2, B3), and 2 red (R1, R2) marbles. (4 points)
1 answer:
The possible outcomes are WH, BH, BH, BH, RH, RH, WL, BL, BL, BL, RL, RL
<h3>How to determine the possible outcomes?</h3>The given parameters are:
Coin = Head (H) and Tail (T)
Marble = W, B, B, B, R, R
See attachment for the tree diagram
From the tree diagram, we have the following possible outcomes
WH, BH, BH, BH, RH, RH, WL, BL, BL, BL, RL, RL
Read more about tree diagram at:
#SPJ1
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Recursive Formula
The top row says the first term is 8
The bottom row says that to get the nth term, we subtract 7 from the (n-1)th term. So basically we subtract 7 from each term to get the next term.
Note the subscripts tell us which term we're working with.
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Arithmetic Formula
We have a = 8 as the first term and d = -7 as the common difference.
a(n) = a + d(n-1)
a(n) = 8 + (-7)(n-1)
a(n) = 8 - 7n + 7
a(n) = -7n+15
The nth term arithmetic formula is a(n) = -7n+15
If you plug in n = 1, you should get a(n) = 8
If you plug in n = 2, you should get a(n) = 1
and so on.
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Finding the 10th term
Plug in n = 10 to get
a(n) = -7n+15
a(10) = -7(10)+15
a(10) = -70+15
a(10) = -55
The 10th term is -55
Answer:
See below.
Step-by-step explanation:
Time taken by (A+B) to finish the work = 12 days
Time Taken by (B+C) to finish the work = 15 days
Time taken by (C+A) to finish the work = 20 days
Therefore,2 ( A + B + C)'s 1 day's work-
Therefore, A, B and C together can finish the work in 10 days.
Now,
A's 1 day's work = (A+B+C)'s 1 day's work - (B+C)'s 1 day's work
- Hence,A alone can finish the work in 30 days.
B's 1 day's work = (A+B+C)'s 1 day's work - (A+C')s 1 day's work
- Hence,B alone can finish the work in 20 days.
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