Factor the following:
10 y^2 - 35 y + 30
Factor 5 out of 10 y^2 - 35 y + 30:
5 (2 y^2 - 7 y + 6)
Factor the quadratic 2 y^2 - 7 y + 6.
The coefficient of y^2 is 2 and the constant term is 6.
The product of 2 and 6 is 12.
The factors of 12 which sum to -7 are -3 and -4. So 2 y^2 - 7 y + 6 = 2 y^2 - 4 y - 3 y + 6 = y (2 y - 3) - 2 (2 y - 3):
5 y (2 y - 3) - 2 (2 y - 3)
Factor 2 y - 3 from y (2 y - 3) - 2 (2 y - 3):
Answer: 5 (2 y - 3) (y - 2)
Answer:
its either family history or morellian analysis , im not sure
Step-by-step explanation:
Answer:
Step-by-step explanation:
The one that doesn't work with the other three is B. Nine cubed is huge compared to just plain 9 or 3^2. The other three each are equal to one another especially if you remove the brackets in D.
9 c^(2*3) * d^(3*3)
9 c^6 d^9
X^3+3x^2+5x+8/x+1
multiply the whole equation by x
x^4+3x^3+5x^2+8+1x
x^4+3x^3+5x^2+x+8
factor out by parts
(x^2-0.641604x+1.33244)(x^2+3.6416x+6.00403)
Answer:
Step-by-step explanation:
Considering the given triangle QED, to determine ED, we would apply the sine rule. It is expressed as
a/SinA = b/SinB = c/SinC
Where a, b and c are the length of each side of the triangle and angle A, Angle B and angle C are the corresponding angles of the triangle. Likening it to the given triangle, the expression becomes
ED/SinQ = EQ/SinD = QD/SinE
Therefore
ED/Sin 49 = 2/Sin 35
Cross multiplying, it becomes
EDSin35 = 2Sin49
0.574ED = 2 × 0.755
0.574ED = 1.51
ED = 1.51/0.574
ED = 2.63 in
