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JulijaS [17]
4 years ago
14

16. The temperature on the ground during a plane's takeoff was -7°F. At 38,000 feet in the air, the temperatureoutside the plane

was -29°F. Find the difference between these two temperatures.a. 36 FC. -22°Fb. 36°Fd. 22 F

Mathematics
1 answer:
Oksana_A [137]4 years ago
4 0
The answer is -22°F because you are subtracing -7°F from -29°F.
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Value of x, of (18, 24, 22, 28,x) mean =25
tankabanditka [31]

Answer:

x = 33

Step-by-step explanation:

Mean = Sum of all the data's/ Number of data's

\frac{18+24+22+28+x}{5}=25\\\\\frac{92+x}{5}=25\\\\92+x=5*25\\\\92+x=125\\\\x=125-92\\\\x=33

8 0
3 years ago
Part A
jek_recluse [69]

Answer:

1.25c

Step-by-step explanation:

c + 0.25c can be written as a single term:  1.25c.

Note that c + 0.25c = 1.00c + 0.25c, and that

1.00c

+0.25c

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1.25c (same as above)

8 0
3 years ago
Ben the camel drinks tea (so classy!). He drinks 350 liters of tea every 2 days.
Eddi Din [679]
Every six days he'd drink 1,050 liters because 

350 liters every 2 days -
 
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700 liters every 4 days - 

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Hope this helps.


4 0
4 years ago
Read 2 more answers
Amar keeps picking playing cards out of a standard deck of 52 cards in the hopes that he will
lapo4ka [179]

Answer:

The required probability is, 0.78

Step-by-step explanation:

There are, (52 - 13) = 39 cards which are not spade

5 cards can be chosen from the deck of 52 cards in

^{52}{C}_{5}  ways

and out of these 5 choices, none of them will be spade in,

^{39}{C}_{5}  ways

So,

P(None of the chosen cards is spade)

= \frac {^{39}{C}_{5}}{^{52}{C}_{5}}

\simeq 0.22

Hence,

P(out of these 5 choices, at least one card is spade)

\simeq (1 - 0.22)

= 0.78

4 0
4 years ago
W-6.67=2.27<br><br> I need help with this
kirza4 [7]
W is equal to 8.94 !!
4 0
3 years ago
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