1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rainbow [258]
2 years ago
6

You are investigating having business cards printed for your new game store. A local printing company charges $250 for the cardb

oard used and an hourly rate for labour of $40.
a. If h is the number of hours of labour required to print the cards, construct an equation for the cost
of the cards, C.

b. You have budgeted $1000 for the printing job. How many hours of labour can you afford? Give
your answer to the nearest minute.

c. The company estimates that it can print 1000 cards per hour of labour. How many cards will you
get printed with your current budget?

d. An alternative to printing is photocopying. The company charges 15 cents per side for the first 10 000 cards and then 10 cents per side for the remaining cards. Which is the cheaper option for 18 750 single-sided cards and by how much?
Mathematics
1 answer:
stellarik [79]2 years ago
7 0

Answer:

See below.

Step-by-step explanation:

<u>a. If h is the number of hours of labour required to print the cards, construct an equation for the cost of the cards, C.</u>

C = $250 + ($40/hr)*h

<u>b. You have budgeted $1000 for the printing job. How many hours of labour can you afford? Give your answer to the nearest minute.</u>

$1000 = $250 + ($40/hr)*h

($40/hr)*h = $750

h = 18.75 hours

(18.75 hours)(60 min/hr) = 1125 minutes

<u>c. The company estimates that it can print 1000 cards per hour of labour. How many cards will you get printed with your current budget?</u>

(18.75 hr)*(1000 cards/hr) = 18,750 cards

<u>d. An alternative to printing is photocopying. The company charges 15 cents per side for the first 10 000 cards and then 10 cents per side for the remaining cards. Which is the cheaper option for 18 750 single-sided cards and by how much?</u>

Photocopy Cost for the first 1000 single-sided cards is:

(1000 cards)*($0.15) = $150

Photocopy Cost for the final 17,750 single-sided cards is:

(17,750)*($0.10) = $1,775

Totoal photocopy cost for 18,750 single-sided cards is $1,925.  [1775+150]

The cheapest option for 18,750 cards is printing:  $1,000

Printing is (1,925 - 1000) $925 cheaper than photocopying.

You might be interested in
Zaire is making granola bars. For one batch of bars, the recipe calls for 1 2/3 cups of rolled oats and ½ cup of raisins. What i
Daniel [21]

Answer:

13/6

No explanation sorry :(

3 0
2 years ago
M-4=2m how to solve this
Phantasy [73]
m-4=2m\\m-2m=4\\-m=4\ \ \ \ \ \ \ \ \ \ \ \ |*(-1)\\m=-4
3 0
3 years ago
Read 2 more answers
Answer for brainliest no files
Alex787 [66]

Answer:

D

Step-by-step explanation:

because its the only one that get the answer 3 2/3 which is the amount shown on the line.

3 0
3 years ago
HELP PELASE ILL MARK BRAINLIEST AND POINTS!
UNO [17]

\qquad\qquad\huge\underline{{\sf Answer}}

Both the given lines in graph intersect at point (5 , -2), the point must satisfy both the equations.

and if we check the options, we will observe that D. option has both the equations that satisfy the given conditions.

that is ~

\qquad \sf  \dashrightarrow \: x + y = 3

put y = - 2,we will get :

\qquad \sf  \dashrightarrow \: x - 2 = 3

\qquad \sf  \dashrightarrow \: x = 5

so, 1st equation satifys the condition. let's check out 2nd one.

\qquad \sf  \dashrightarrow \: x + 2y = 1

put y = -2

\qquad \sf  \dashrightarrow \: x + (2 \times  - 2) = 1

\qquad \sf  \dashrightarrow \: x - 4 = 1

\qquad \sf  \dashrightarrow \: x = 5

Hence, we can conclude that the Correct choice is D

5 0
2 years ago
For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 63 N acts on
Luba_88 [7]

Answer:

18 N

Step-by-step explanation:

Let <em>F</em> denote the force, <em>m</em> denote the mass of the object and <em>a </em>denote the acceleration of the object.

<em />F=ma<em />

m = \frac{F_{1} }{a_{1} }=\frac{63}{7} =9 kg

F_{2} =ma_{2}=9*2=18N

6 0
3 years ago
Other questions:
  • Cual es la regla de la sucesión 2,5,10,17,26, ,
    13·1 answer
  • Give a combinatorial proof that the cardinality of the power set of a finite set A is 2^|A|
    5·1 answer
  • Find t20 for the arithmetic sequence in which t1 = 36 and t3 = 28,
    15·1 answer
  • 10.2 = 20 is rewritten as 2.10 = 20. Was this
    12·1 answer
  • Solve:<br> 2 3/4 −(−1 1/2 )+(− 5/6 )−(− 3/8)−(+4 2/3 )<br> PLS HELP!
    13·2 answers
  • It’s worth 10 points if you answer!
    15·1 answer
  • Which of the following sets can be three angles of a triangle?
    12·1 answer
  • 2(x+1)=3x <br><br> can you show the steps to get the answer as well please
    12·2 answers
  • Find each equation with the correct solution​
    11·1 answer
  • what are all the square numbers
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!