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NeX [460]
1 year ago
15

In order to get good results in relation to observing water pressure at fixtures, it is good inspection procedural practice to i

nspect the plumbing fixtures at the
SAT
1 answer:
Lana71 [14]1 year ago
6 0

In order to get good results in relation to observing water pressure at fixtures, it is good inspection procedural practice to inspect the plumbing fixtures at the "pressure gauges"

<h3>What is plumbing fixtures?</h3>

Plumbing fixtures are the devices that can be linked with a plumbing system to deliver fluid or drain it.

<h3 />

It is common practice for these system to be fitted with a pressure gauges.

Learn more about plumbing fixtures at;
brainly.com/question/12713589
#SPJ1

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During last year's basketball season, Jackson attempted
OLga [1]

This question is incomplete and not well written.

Complete question:

During last year's basketball season, Jackson attempted

150 free throws of which he made

120. So far this season, he's attempted 24 and made 16. A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted. Assuming calculations began with the start of last year's season, which of the following best approximates Jackson's overall free-throw percentage to date?

A. 67%

B. 73%

C. 78%

D. 80%

Answer:

B. 73%

Explanation:

In the question, we are told that:

A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted

Mathematically

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted)× 100

For Last year, Jackson attempted

150 free throws of which he made

120

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (120÷150) × 100

= 80%

This season, he's attempted 24 and made 16

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (16÷24) × 100

= 66.67%

Approximately = 67%

The best approximation for Jackson's overall free-throw percentage to date is

(Percent Free Throw for last season + Percent Free Throw for this season) ÷ 2

Percent Free Throw for last season

= 80%

Percent Free Throw for this season = 66.67%

Therefore, (80% + 66.67%) ÷ 2

= 146.67% ÷ 2

= 73.335%

Approximately = 73%

Therefore, Jackson's overall free-throw percentage to date is 73%

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