Based on the graph given, it can be deduced from the computation that the value of y will be -8.
Point C is given as (-10 , -2) and D = (10 , 6)
The Slope of line CD = ( 6 - (-2) /( 10 - (-10) = 8/20 = 2/5
Since EF is parallel to line CD
, the slope of EF = 2/5
Equation y = (2/5)x + c
5y = 2x + 5c
It passes through F ( 6 , -4)
= 5(-4) = 2*6 + 5c
= -20 = 12 + 5c
5c = -32
5y = 2x - 32
Point E ( - 4 , y)
5y = 2(-4) - 32
5y = -8 - 32
5y = -40
y = -8
Therefore, the value of y is -8.
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Answer:
-5x+4y=20
Explanation:
A line passes through point (-8, -5) and has a slope of 5/4
Write an equation in Ax+By=C form for this line.
Use integers for A, B, and C.
So we have a point and a line we can use the point slope formula
y-y1=m(x-x1)
y-(-5)=(5/4)(x- -8)
y+5=(5/4)(x+8)
y=5/4x+10-5
y=5/4x+5
Then we multiply 4 both sides
4y=5x+20
-5x+4y=20