a. See attachment for the labelled diagram
b. Using the sine ratio, distance from the hot air to pond A is 5,038.9 m, while distance from the hot air to pond B is 6,287.1 m.
c. Distance between the two ponds is 1,263.5 m.
<h3>What is the Sine and Tangent Ratios?</h3>Sine ratio, is: sin ∅ = opposite side/hypotenuse length
Tangent ratio is: tan ∅ = opposite side/adjacent length.
a. The diagram with the appropriate labels is shown in the image attached below.
b. Use the sine ratio to find the distance from the hot air to pond A (CA) and to pond B (CB):
CA = hypotenuse
∅ = 10°
Opposite = 875 m
sin 10 = 875/CA
CA = 875/sin 10
CA ≈ 5,038.9 m (distance from the hot air to pond A)
CB = hypotenuse
∅ = 8°
Opposite = 875 m
sin 8 = 875/CB
CB = 875/sin 8
CB ≈ 6,287.1 m (distance from the hot air to pond B)
c. Distance between the two ponds, BA = BD + DA.
Apply the tangent ratio to find BD and DA
tan 8 = 875/BD
BD = 875/tan 8
BD = 6,225.9 m
tan 10 = 875/DA
DA = 875/tan 10
DA = 4,962.4 m
Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.
Learn more about the sine and tangent ratios on:
#SPJ1
Given that,
In <u>triangle TPQ, </u>
As it is given that, <u>RS || PQ</u>
So, it means
⇛∠TRS = ∠TPQ [ Corresponding angles ]
⇛ ∠TSR = ∠TPQ [ Corresponding angles ]
<u>Now, We know </u>
Area Ratio Theorem,
This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.
Answer:
The experamental probability that the coin lands on head is 50 %
Step-by-step explanation:
Given:
Experiment:
A coin is Toss
Let the Sample Space be 'S' that is total number of outcomes for a coin has been tossed = { Head, Tail }
∴ n ( S ) = 2
Let A be the event of getting a Head on tossing a coin i.e { Head }
∴ n( A ) = 1
Now,
Substituting the values we get
The experamental probability that the coin lands on head is 50 %