Let x and y be the length and width of the rectangle respectively
2(x+y)=32...(1)
x=2y-5...(2)
From (1),we have
2x+2y=32...(3)
By sub.(2) into (3),we have
2(2y-5)+2y=32
4y-10+2y=32
6y=42
y=7
By sub.y=7 into (2),we have
x=2*7-5
x=14-5
x=9
Length =9m
Width =7m
I thinks 5 because -2(x) = -2x and -2(5)=-10
So -2x=-10
-10/-2=5
X=5
We can use quadratic formula to determine the roots of the given quadratic equation.
The quadratic formula is:

b = coefficient of x term = -11
a = coefficient of squared term = 2
c = constant term = 15
Using the values, we get:
So, the correct answer to this question are option B and D
Answer:
8
Step-by-step explanation:
Count each side and you get 8 sides.
The opposite sides of a rectangle will always be congruent. If they aren't, it's not a rectangle.
To find CD, you need to find what z is. This can be found using the given, the perimeter, and plugging that into the perimeter formula using the information given. You end up with 2(4z - 3) + 2(3z - 1) = 132. Solve for z and you find that z = 10.
CD is congruent to AB, which is 3z -1. Plug z in to get AB = 29. Since AB = CD, CD = 29.