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Hoochie [10]
2 years ago
14

When graphing the inequality y ≤ 2x − 4, the boundary line needs to be graphed first. Which graph correctly shows the boundary l

ine? A. A linear inequalities graph of dotted boundary line intersects X-axis at the unit (2, 0) and Y-axis at the unit (0, minus 4) B. A linear graph of solid line intercepts X-axis at the unit (2, 0) and Y-axis at the unit (0, minus 4) C. A linear inequalities graph of dotted boundary line intercepts at the X-axis (0.5, 0) and Y-axis (0, 2) D. A linear graph of a solid boundary line intersects X-axis at the unit (0.5, 0) and Y-axis at the unit (0, 2)
Mathematics
2 answers:
Natali5045456 [20]2 years ago
4 0

Answer:

  B.  A linear graph of solid line intercepts X-axis at the point (2, 0) and Y-axis at the point (0, -4)

Step-by-step explanation:

The boundary line of an inequality is graphed as though the expression were an equality. The nature of the line used will depend on the nature of the inequality.

<h3>Form of the line</h3>

When the inequality includes the "or equal to" case (≤ or ≥), the boundary line is part of the solution set. It is drawn as a solid line.

When the inequality excludes the "or equal to" case (< or >), the boundary line is not part of the solution set. It is drawn as a dotted or dashed line.

The given inequality

  y ≤ 2x -4

includes the "or equal to" case, so the boundary line is solid.

<h3>Y-intercept</h3>

The equation of the boundary line is written in slope-intercept form:

  y = mx +b . . . . . . . line with slope m and y-intercept b

  y = 2x -4 . . . . . . . boundary line with slope 2 and y-intercept -4.

This tells you that the boundary line intercepts the y-axis at the point (0, -4).

Savatey [412]2 years ago
3 0

The correct graph is in the attached image.

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