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Kay [80]
3 years ago
8

Solve each equation by taking square roots 8v^2 +3=35

Mathematics
1 answer:
makvit [3.9K]3 years ago
4 0
8v^2 +3=35 

8v^2=35-3

 
      Subtract \ 3 \ from  \ both \ sides


8v^2=32
 
 

v^2= \dfrac{32}{8}   Divide \ both \ sides \ by \ 8

v^2=4 


v=+ \sqrt{4} 
 
            Take \ the \ square \ root \ of \ both \ sides


v=+2
 

 
                       \ Since \ 2*2=4, \ the \ square \ root \ of \ 4  \ is  \ 2
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The temperature of a solution in a science experiment is -4.3°C. Mark wants to raise
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Answer:

If it's -20 degrees outside and it decreases 3 degrees what

temperature is it?  I know the answer is -23 degrees but it seems like

it should be -17 degrees.  When do you have to change the sign into

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Date: 01/08/2004 at 12:13:38

From: Doctor Peterson

Subject: Re: word problems with negative integers

Hi, Jonah.

It may help to look at an actual thermometer. It will look something

like this:

   |

   + 40

   |

   + 30

   |

   + 20

   |

   + 10

   |         ^

   + 0      / \

   |         |

   + -10     | warmer (increasing temperature)

   |         |

   + -20 ----+

   |         |

   + -30     | colder (decreasing temperature)

   |         |

   + -40    \ /

   |         V

Suppose it was -20 degrees an hour ago, and now it has gone down 10

degrees.  As it goes down, it will get farther away from 0 (since it

is below zero to start with), so it will decrease from -20 degrees

to -30 degrees!  The number part (the 30, which is the "absolute

value" of the temperature) increases because we are going away from

zero while the temperature itself decreases (getting colder).  If the

temperature changed to -10, it would be warmer, not colder; that would

be an increase in temperature.

Does that make sense?

- Doctor Peterson, The Math Forum

 http://mathforum.org/dr.math/

Date: 01/08/2004 at 12:09:15

From: Doctor Rick

Subject: Re: word problems with negative integers

Hi, Jonah.

It's easier to understand the correct answer if you look at a

thermometer.  If it had every degree labeled, portions of it would

look like this:

  5 | |

  4 | |

  3 | |

  2 | |

  1 | |

  0 | |

 -1 | |

 -2 | |

 -3 | |

 -4 | |

 -5 | |

 -6 | |

.........

-18 | |

-19 | |

-20 |-|  *

-21 | |  | down 3

-22 | |  V

-23 | |  *

-24 | |

-25 | |

If you're at -20 and you go DOWN (decrease) 3 degrees, you get to -23.

Now, to do it mathematically instead of looking at the thermometer,

we do this:

 -20 - 3

which is the same as

 -20 + (-3)

Subtracting is always the same as adding the opposite.  Now, if you're

familiar with the distributive property, we can remember that the

negative sign means to multiply by -1, and we can do that

multiplication just once:

 (-1*20) + (-1*3) = -1*(20 + 3)

                  = -1*23

                  = -23

In other words, the rule for adding two negative numbers is to add

the numbers without the negative signs, then make the result negative.

If we wanted to INCREASE the temperature 3 degrees, we would do this:

 -20 + 3

I can again factor out a -1 like this:

 (-1*20) + (-1*-3)

because 3 divided by -1 is -3.  Then combine the -1's with the

distributive property:

 -1(20 + -3) = -1(20 - 3)

             = -1*17

             = -17

A rule to remember here is that if you are adding two numbers with

DIFFERENT signs, you subtract the smaller from the bigger (ignoring

the negative sign), and give the answer the sign of the bigger

number.  In this problem, -20 + 3, we look at 20 and 3, subtract 3

from 20 to get 17, then since the bigger number (20) has the negative

sign, we make the answer negative: -17.

I hope this helps you!

- Doctor Rick, The Math Forum

 http://mathforum.org/dr.math/

Associated Topics:

Elementary Temperature

Middle School Negative Numbers

Middle School Temperature

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