Question

What is the area of the trapezoid above?

Answer 1

Answer:

• B. 196cm²

Step-by-step explanation:

Area = h/2 (b_1+b_2)

$\sf\cfrac{7}{2}\:(22+34)$

Add 22 and 34 = 56

$\sf \cfrac{7}{2} \times 56$

Let's express 7/2 * 56 as a single fraction:-

$\sf \cfrac{7\times 56}{2}$

Multiply 7 and 56 = 392

$\sf \cfrac{392}{2}$

Divide

$\sf 196$

Therefore, the area of the trapezoid is 196cm².

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