Answer:
Male Fish = 20
Female Fish = 16
Step-by-step explanation:
Let number of male fish be x and number of female fish be y
There are 36 fishes in total, so we can write:
x + y = 36
or
x = 36 - y
Also, male fish (x) cost 5 each and female fish (y) cost 7 each totalling $212, so we can write:
5x + 7y = 212
Now, we can put 1st equation in 2nd equation and get an equation in "y" and solve for y first:
We know x = 36 - y, so
x = 36 - 16
x = 20
Thus,
there are
20 Male fishes & 16 female fishes in the aquarium
Left side:
x+x+x+1+1+1+1+1+1+1+1 = 3x + 8
Right side:
x+x+x+x++1+1+1+1+1+1
Left side = Right side to solve x
3x + 8 = 4x + 6
Subtract 4x from both sides
3x + 8 - 4x = 4x + 6 - 4x
Simplify
-x + 8 = 6
Subtract 8 from both sides
-x + 8 - 8 = 6 - 8
Simplify
-x = -2
Multiply both sides by (-1)
-x * (-1) = -2 * (-1)
Simplify
x = 2
Answer
C. x = 2
Since the basis is from year 1 to year 2, calculate first for the difference of their percentages. That would be:
Difference = year 2 - year 1
Difference = 2.32% - 1.1% = 1.22%
We apply this same value of percentage increase from year 2 to year. Thus, the percentage for year 3 is:
% Year 3 = % Year 2 + percentage increase
% Year 3 = 2.32% + 1.22%
% Year 3 = 3.54%
