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alexdok [17]
2 years ago
9

Kaitlin, Joe, and Miguel have a total 96 of in their wallets. Kaitlin has 6 less than Joe. Miguel has 4 times what Joe has. How

much does each have?
Mathematics
1 answer:
schepotkina [342]2 years ago
4 0

Answer:

15, 11, 60

Step-by-step explanation:

Let Joe's amount be x

x + x - 6 + 4x = 96

6x - 6 = 96

6x = 90

x = 15

Joe has 15

Kaitlin has 11

Miguel has 60

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dybincka [34]

Answer:

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Step-by-step explanation:

The composite function is ...

  M(B(L(h))) = M(B(28.75h)) = M(1.78(28.75h)) = M(51.175h)

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The composite function is ...

  M(h) = M(B(L(h))) = 73.18025h

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3 years ago
A die is rolled twice. What is the probability of showing a 1 on the first roll and an even number on the second roll?
Ivan

Answer:

1/12

Step-by-step explanation:

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Furthermore, there are 3 different even numbers on a 6-sided die, so that is 3/6, which can be simplified to 1/2.

Now, because this is a compound probability, we have to multiply 1/2 and 1/6 together, which would give us our answer of 1/12.

6 0
3 years ago
Read 2 more answers
How do you solve 163-x= -52
DanielleElmas [232]

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Answer: 72.4

Step-by-step explanation:

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