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Iteru [2.4K]
2 years ago
14

2. CHARITY Luis was in charge of collecting money for

Mathematics
1 answer:
topjm [15]2 years ago
4 0

Answer:

89$ for 11 Charities

Step-by-step explanation:

I. If Luis has $979 and he wants to give it to 11 charities right?

  So  \frac{979}{11}

    = 89$

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Integral of x"2+4/x"2+4x+3
dolphi86 [110]

I'm guessing you mean

\displaystyle \int\frac{x^2+4}{x^2+4x+3}\,\mathrm dx

First, compute the quotient:

\displaystyle \frac{x^2+4}{x^2+4x+3} = 1 + \frac{4x-1}{x^2+4x+3}

Split up the remainder term into partial fractions. Notice that

<em>x</em> ² + 4<em>x</em> + 3 = (<em>x</em> + 3) (<em>x</em> + 1)

Then

\displaystyle \frac{4x-1}{x^2+4x+3} = \frac a{x+3} + \frac b{x+1} \\\\ \implies 4x - 1 = a(x+1) + b(x+3) = (a+b)x + a+3b \\\\ \implies a+b=4 \text{ and }a+3b = -1 \\\\ \implies a=\frac{13}2\text{ and }b=-\frac52

So the integral becomes

\displaystyle \int \left(1 + \frac{13}{2(x+3)} - \frac{5}{2(x+1)}\right) \,\mathrm dx = \boxed{x + \frac{13}2\ln|x+3| - \frac52 \ln|x+1| + C}

We can simplify the result somewhat:

\displaystyle x + \frac{13}2\ln|x+3| - \frac52 \ln|x+1| + C \\\\ = x + \frac12 \left(13\ln|x+3| - 5\ln|x+1|\right) + C \\\\ = x + \frac12 \left(\ln\left|(x+3)^{13}\right| - \ln\left|(x+1)^5\right|\right) + C \\\\ = x + \frac12 \ln\left|\frac{(x+3)^{13}}{(x+1)^5}\right| + C \\\\ = \boxed{x + \ln\sqrt{\left|\frac{(x+3)^{13}}{(x+1)^5}\right|} + C}

3 0
2 years ago
Please answer this thanks
Arlecino [84]

Answer:

$66.24

Step-by-step explanation:

TIP:

55.20 x 0.15 = 8.28

TAX:

55.20 x 0.05 = 2.76

Answer:

55.20 + 8.28 + 2.76 = 66.24

(Also always tip your server 20% unless they were bad)

7 0
2 years ago
each tissue box has a volume of 125 cubic inches. the estimate volume of the box holding the issue boxes is​
Ann [662]

Answer:

The estimate volume of the box holding the tissue boxes V;

V = nv = 9×125

V = 1125 cubic inches

Attached is an image for further understanding of the question;

Step-by-step explanation:

Given;

Volume of each tissue box v = 125 cubic inches

Number of tissues n from the attached image;

n = 3×3 = 9 tissue boxes

The estimate volume of the box holding the tissue boxes V;

V = nv = 9×125

V = 1125 cubic inches

8 0
2 years ago
Tom needs $150.00 to buy a stereo. Right now, he has $90.00.
djyliett [7]

Answer:

I think 60.00 is the answer

Step-by-step explanation:

hope you like my answer

4 0
3 years ago
Read 2 more answers
A nut mixture of peanuts and macadamia nuts at a small fair is $1.00 per pound of peanuts and $3.26 per pound of macadamia nuts.
Salsk061 [2.6K]

Answer:

D

Step-by-step explanation:

You can infer to the solution of this problem by looking at the choices. Hope this helped :)

7 0
2 years ago
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