1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Umnica [9.8K]
2 years ago
5

Annual starting salaries for college graduates with degrees in business administration are generally expected to be between and

. Assume that a confidence interval estimate of the population mean annual starting salary is desired. a. What is the planning value for the population standard deviation
Mathematics
1 answer:
kenny6666 [7]2 years ago
4 0

The planning value for the population standard deviation is 4330.

Given the confidence interval 20000 and 35000.

We have to find the planning value of standard deviation.

Standard deviation is measuring dispersion of data. Uniform probability distribution has two bounds a and b. The standard deviation is given by :

s=\sqrt{(b-a)^{2}/12 }.

Annual starting salaries for college graduates be between 20000 and 35000.

It is uniform in the interval so, a=20000, b=35000.

Now we have to just put the values of a and b in the above formula to get the value of standard deviation.

s=\sqrt{(35000-20000)^{2} /12}

=\sqrt{(15000)^{2} /12}

=\sqrt{225000000/12}

=\sqrt{18750000}

=4330

Hence the planning values for the population standard deviation is 4330.

Learn more about standard deviation at brainly.com/question/475676

#SPJ1

Question is incomplete as it should includes the confidence interval of $20000 and $35000.

You might be interested in
CRACK the CODE
Studentka2010 [4]

Answer:

yea i dont know this one bro

Step-by-step explanation:

4 0
3 years ago
417.80+350+150+5.25-(215.85-i)=555.82
motikmotik
583.08 is the answer
4 0
4 years ago
Read 2 more answers
Find the coordinates of the midpoint of a line segment with end points (-3,4) and (7,9)
lesantik [10]

Answer:  (2, 6.5)

<u>Step-by-step explanation:</u>

Midpoint_{x,y}=\bigg(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\bigg)\\\\\\.\qquad \qquad \quad=\bigg(\dfrac{-3+7}{2},\dfrac{4+9}{2}\bigg)\\\\\\.\qquad \qquad \quad=\bigg(\dfrac{4}{2},\dfrac{13}{2}\bigg)\\\\\\.\qquad \qquad \quad=\large\boxed{(2,6.5)}

6 0
3 years ago
$5000 at a 5% interest for 3 1/2 years
larisa [96]
5,875 is the answer
4 0
3 years ago
Party planners recommend that, for every eight guests, two orders of appetizers be provided. Which function reflects this ratio?
Bond [772]

STEP - BY - STEP EXPLANATION

What to find?

The function that reflects the given ratios given.

Given:

For every eight guests, 2 orders.

To determine the function;

Let y be the number of orders and x be the number of guests.

If for every eight guest, there must be 2 orders, then we will have;

y=\frac{1}{4}x

So that, if there are 8 guests, that is; when x=8

y=\frac{1}{4}(8)=2

ANSWER

y= 1/4 x

8 0
1 year ago
Other questions:
  • Rosita and Garth are saving up for a vacation, and begin with a certain amount saved each. If Rosita works 5 hours, she will hav
    7·1 answer
  • F x equals 3x squared + 6 x - 7
    10·2 answers
  • the next Science test will have 50 questions.How many questions does Julia need to answer correctly to recieve a score of 90%
    9·2 answers
  • The ratio of boys to girls in Fiona's class is
    13·1 answer
  • F+ 20 = -1<br> Solve the equation and check your solution
    15·1 answer
  • Într-un cimitir există 7 chiparoși și 288 tufe de tuia. La fiecare mormânt există cel puțin o tufă de tuia. Numărul celor cu dou
    8·1 answer
  • Sebastián está haciendo un curso de patinaje. El primer día recorrió una distancia de
    7·1 answer
  • *6. Five brothers each bought two hot dogs &amp; a bag of chips. If the chips
    6·2 answers
  • Which of the following is equal to 6 - (-5) ?<br> A -11<br> B 1<br> C 11
    8·2 answers
  • What is the explicit arithmetic sequence formula for 72, 48, 24,....?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!