Answer:
I'm not sure how to solve the question what kind of math is it
Answer:19683x
Step-by-step explanation:
Evaluate the exponent
27.93x
27.729x
i am pretty sure sorry if I am wrong
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:
Trump
Step-by-step explanation:
Answer:
y = 4
since you cant have y = 0x + 4, you drop the x and have a straight line (slope of 0) that runs all along the y point of 4.
