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Nataliya [291]
1 year ago
11

Find all pairs of prime numbers (a,b) such that a^b✖️b^a+1 is prime

Mathematics
1 answer:
Alenkasestr [34]1 year ago
5 0

The pairs of prime numbers (a,b) between 1 and 10 inclusive such that a^b * b^a+1 is prime are

<h3>How to determine the pairs of numbers?</h3>

The expression that is a prime number is given as:

a^b * b^a + 1

The boundary or range of numbers of a and b is not given.

So, we make use of numbers between 1 and 10

i.e. 1 ≤ a ≤ 10 and 1 ≤ b ≤ 10

Using the above range, we have the following program to determine the pairs of prime numbers (a, b).

for a in range(1,11):

   for b in range(1,11):

       num = (a* *b) * (b* *a) + 1

       flg = False

       if num > 1:

           for i in ra nge(2, num):

               if (num % i) == 0:

                   flg = True

                   break

       if not flg:

           print(str(a)+","+str(b))

The output of the above program is:

(1,1), (1,2), (1,4), (1,6), (1,10), (2,1), (2,2), (2,3), (2,4), (3,2), (4,1), (4,2), (4,4) and (4,6)

The above represent all pairs of prime numbers (a,b) such that a^b * b^a+1 is prime

Read more about prime numbers at:

brainly.com/question/25710806

#SPJ1

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X representa o numero das suas respostas certas.
y represnta o numero das suas respostas erradas.
O total de perguntas <span>é 25, portanto
x + y = 25

Agora tratamos do dinheiro.
Come</span>ça com <span>R$ 500,00
Pelas x respostas certas, recebe 200x.
Pelas y respostas errads perde 150y.
O total de dineheiro inicial mais os ganhos menos as perdas s</span>ão iguais a
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Temos um sistema de duas equações com duas variaveis.

<span>x + y = 25</span>
20x - 15y = 10

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---------------------------
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