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crimeas [40]
3 years ago
15

Solve the system of equations -2x+5y=13 16x+3y=25

Mathematics
2 answers:
rosijanka [135]3 years ago
8 0

-2x+5y=13
-5 -5
=8
-2(negative two)
-2 /8 =???
That's how to find answer
qwelly [4]3 years ago
6 0
-2x + 5y = 13
16x + 3y = 25

To solve this you have to cancel the x first so you multiply the first equation by 8

-2x + 5y = 13. All of that times 8
-16x + 40y = 104


Now that you have this you can cancel x

-16x + 40y = 104
16x. +. 3y. = 25

X cancel

40y = 104
3y. = 25

You add the y and the numbers

43y = 129
/43. /43

Y = 3


Now you plug y in one of the equations

16x + 3y = 25
16x.+ 3(3) = 25
16x + 9 = 25
-9. -9

16x = 16
/16. /16

X = 1



Y = 3 and X = 1
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3 years ago
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Solve for x:<br> 2(3x + 4) + 2 = 4 + 3x
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-2

Step-by-step explanation:

Distribute

2

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+

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{\color{#c92786}{6x+8}}+2=4+3x

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Add the numbers

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6x+{\color{#c92786}{10}}=4+3x

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Rearrange terms

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6x+10={\color{#c92786}{3x+4}}

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4

Subtract  

1

0

10

10

from both sides of the equation

6

+

1

0

=

3

+

4

6x+10=3x+4

6x+10=3x+4

6

+

1

0

−

1

0

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3

+

4

−

1

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Simplify

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Simplify

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8

Divide both sides of the equation by the same term

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9

Simplify

Cancel terms that are in both the numerator and denominator

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−

2

3 0
3 years ago
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Help me please it's do today and i'm stuck on this one
Feliz [49]

Answer:G

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Hope it helps.

5 0
3 years ago
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