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3 years ago

18 of the 30 horses were blue what percent of the Horseshoe blue

Mathematics

1 answer:

Minchanka [31]3 years ago

6 0

18 divided by 30 equals .6
0.6=60%
Hope this helps and please give brainliest!

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Helppppp pleaseeee!!!!!!!!<br> (Show the work)

Vikentia [17]

Answer:

Step-by-step explanation:

ABD (half of the rectangle) is a right-angled triangle.

so, Pythagoras applies.

c² = a² + b²

c is the Hypotenuse (the baseline opposite of the 90 degree angle) and in our case the line BD.

a and b are the 2 sides enclosing the 90 degree angle. in our case here the lines AD and AB.

so,

BD² = AD² + AB² = (6-1)² + (5-2)² = 5² + 3² = 25 + 9 = 34

BD = sqrt(34)

7 0

3 years ago

Follow the process of completing the square to solve x^2 - 10x + 8 = 0. What is the value of the constant that will be isolated

My name is Ann [436]

To solve using completing square method we proceed as follows:
x^2-10x+8=0
x^2-10x=-8
but
c=(b/2)^2
c=(10/2)^2=25
thus we can add this in our expression to get
x^2-10x+25=8+25
factorizing the LHS we get:
(x-5)(x-5)=33
(x-5)^2=33
getting the square roots of both sides we have:
x-5=+/-√33
x=5+/-√33

7 0

3 years ago

Read 2 more answers

Select the correct answer from each drop-down menu.

podryga [215]

Answer with explanation:

$\text{Average}=\frac{\text{Sum of all the observation}}{\text{Total number of Observation}}$

Average Height of tallest Building in San Francisco

$=\frac{260+237+212+197+184+183+183+175+174+173}{10}\\\\=\frac{1978}{10}\\\\=197.8$

Average Height of tallest Building in Los Angeles

$=\frac{310+262+229+228+224+221+220+219+213+213}{10}\\\\=\frac{2339}{10}\\\\=233.9$

→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco

=233.9-197.8

=36.1

⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.

⇒Part B

Mean absolute deviation for the 10 tallest buildings in San Francisco

|260-197.8|=62.2

|237-197.8|=39.2

|212-197.8|=14.2

|197 -197.8|= 0.8

|184 -197.8|=13.8

|183-197.8|=14.8

|183-197.8|= 14.8

|175-197.8|=22.8

|174-197.8|=23.8

|173 -197.8|=24.8

Average of these numbers

$=\frac{62.2+39.2+14.2+0.8+13.8+14.8+14.8+22.8+23.8+24.8}{10}\\\\=\frac{231.2}{10}\\\\=23.12$

Mean absolute deviation=23.12

5 0

3 years ago

Suppose you and your 4 friends (5 people) are dressing up as the 6 main characters of the first Avengers movie: Iron Man, Hulk,

Dennis_Churaev [7]

Answer:

720

Step-by-step explanation:

If every person has to choose a different character, the first person to choose a character has 6 options, the second has 5, the third has 4, the fourth has 3, and the last person has only two options. Therefore, the total number of ways you can do this if all 5 people dress up as a different character is:

$n=6*5*4*3*2\\n=720$

There are 720 ways.

5 0

3 years ago

Please answer I really need help with these just answer at least one.

aleksandrvk [35]

.50(150)+30=$105
8(32)+12 = $268

7 0

2 years ago