Ask question

Ask question

All categories

2 years ago

7

PLS HELP Use the divisibility rules to determine which of the following numbers 315 is divisible by.(Check all that apply.) 2 3

5 7 11

1 answer:

timama [110]2 years ago

5 0

The number is divisible by 3, 5, and 7

You might be interested in

Help me on all of the questions below plz

Lubov Fominskaja [6]

1- The answer is that she wants the new time to be 32 minutes

Solution: The question asks that she wants to DECREASE by 20%

What you will do it convert 20% to a decimal (which is 0.20)

Then, you need to multiply the minutes by the decimal:

40 x 0.20 = 8 minutes

Now you know that 8 minutes will be 20% of 40 minutes, so you just subtract 8 from 40 UwU

7 0

2 years ago

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

or

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

or

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

2 years ago

Please help me :( I’m struggling

QveST [7]

Answer:

im assuming its b because the quality for the pic is bad and i cant really see it

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Parallelogram abcd is divided into two triangles along diagonal ac. if you know the area of the parallelogram, how do you find t

Lera25 [3.4K]

Answer :- Just try area/2 or half the area of the triangle

6 0

3 years ago

Read 2 more answers

Complete the table and write the equation for the relationship shown in the graph.

SVEN [57.7K]

8 = 1. The relationship equation is y = x - 7

4 0

3 years ago