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Ann [662]
2 years ago
11

A rectangle has a side length of two and seven eighths feet and a side width of 5 feet. What is the area of the rectangle?

Mathematics
1 answer:
Elza [17]2 years ago
6 0

Answer:

14 3/8 ft^2

Step-by-step explanation:

Area = length * width

=   2 7/8 * 5

=  23/8 * 5

= 115/8

= 14 3/8 ft^2.

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Please please please helpppp, (please show work if you can)
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Answer:

∴ m∠KIJ = 18°  and   m∠HIJ = 50°

Thus, option a is correct.

Step-by-step explanation:

From the figure, it is clear that:

m∠KIH = m∠HIJ + m∠KIJ

Given

  • m∠KIH = 68°
  • m∠KIJ = (2x + 6)°
  • m∠HIJ = (9x - 4)°

now substituting m∠KIH = 68°, m∠KIJ = (2x + 6)° and m∠HIJ = (9x - 4)° in the equation

m∠KIH = m∠HIJ + m∠KIJ

68° = (2x + 6)° + (9x - 4)°

switch sides

\left(2x+6\right)+\left(9x-4\right)=68

Group like terms

2x+9x+6-4=68

11x+2=68

Subtract 2 from both sides

11x+2-2=68-2

Simplify

11x=66

Divide both sides by 11

\frac{11x}{11}=\frac{66}{11}

Simplify

x=6

Hence, the value of x = 6

Therefore,

m∠KIJ = (2x + 6)° = 2(6) + 6 = 12 + 6 = 18°

m∠HIJ = (9x - 4)° = 9(6) - 4 = 54 - 4 = 50°

∴ m∠KIJ = 18°  and   m∠HIJ = 50°

Thus, option a is correct.

8 0
3 years ago
Is this correct ? if not what’s the correct answer?
JulsSmile [24]

Answer:

Yes that is correct

Step-by-step explanation:

56+56+68 = 180

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2 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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