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IrinaK [193]
2 years ago
8

Using the data in the table, which statement is true?

Mathematics
1 answer:
Igoryamba2 years ago
3 0

The true statement is mean > median

<h3>How to determine the true statement?</h3>

The mean is the average value.

So, we have

Mean = Sum/Count

This gives

Mean = (8 * 1 + 10 * 3 + 14 * 2)/(1 + 3 + 2)

Evaluate

Mean = 11

The mode is the measure with the highest frequency.

So, we have

Mode = 10

The median is the middle element

So, we have

Median = 10

The mean (11) is greater than the mode and the median

Hence, the true statement is mean > median

Read more about mean, median and mode at:

brainly.com/question/15323584

#SPJ1

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Allushta [10]

Answer:

The answer is D: -y^4

Step-by-step explanation:

(-1/y^-4) = -1(y^4)/1 = -y^4

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2 years ago
(HELP PLEASE) It costs $68 for 16 square feet of flooding. How much does it cost for 12 square feet of flooring?
FromTheMoon [43]

Answer:

12 feet of flooring cost $51

Step-by-step explanation:

68/16 = 4.25

4.25 x 12 = 51

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Suppose you invest $400 at an annual interest rate 7.6% compounded continuously. How much will you have in the account after 1.5
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3 0
3 years ago
Your Statistics group wanted to determine what percent of Dulles High School senior like pineapple on their pizza. You randomly
balu736 [363]

Answer:

The answer is "0.1040"

Step-by-step explanation:

Margin of error=Z_{\frac{\alpha}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\\\\

                          =Z_{\frac{0.10}{2}} \sqrt{\frac{\frac{36}{60}(1-\frac{36}{60})}{60}}\\\\=1.645 \times 0.0632\\\\=0.1040\\\\

7 0
2 years ago
A programmer plans to develop a new software system. In planning for the operating system that he will​ use, he needs to estimat
erma4kov [3.2K]

Answer:

a) n = 9604

b) n = 381

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

a. Assume that nothing is known about the percentage of computers with new operating systems. n = ?

When we do not know the proportion, we use \pi = 0.5, which is when we are going to need the largest sample size.

The sample size is n when M = 0.01.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.01\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.01}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.01})^{2}

n = 9604

b. Assume that a recent survey suggests that 99% of computers use a new operating system. n = ?

Now we have that \pi = 0.99. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.96\sqrt{\frac{0.99*0.01}{n}}

0.01\sqrt{n} = 1.96*\sqrt{0.99*0.01}

\sqrt{n} = \frac{1.96*\sqrt{0.99*0.01}}{0.01}

(\sqrt{n})^{2} = (\frac{1.96*\sqrt{0.99*0.01}}{0.01})^{2}

n = 380.3

Rouding up

n = 381

7 0
3 years ago
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