A fair die is rolled 4 times. What is the probability of having no 3 and no 4 among the rolls? Round your answer to three decima
1 answer:
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Step-by-step explanation:
[tex] - 24 \div 4 = \\ \frac{ - 24}{4} \\ = \frac{ - 12}{2} \\ = /frac{-6}{1}