The answer to this question is (6,-1)
F(1) = 1^3 + 3(1)^1 - 3 - 1 = 1 + 3 - 3 - 1 = 0
so one zero is x = 1, and x-1 is a factor
dividing f(x) by x - 1 gives x^2 + 4x + 1
x = [-4 +/- sqrt (16 - 4)] / 2
x = -0.27, -3.73
zeroes are 1 , -0.27 and -3.73 Answer
X and y represent the two students.
Teacher wants to spend at least $5 in each of x and y. That means x or y could be either equal to 5 or higher than 5.
x ≥ 5
y ≥ 5
Teacher only spends under $30. That means the sum of x and y couldn't be equal to higher than 30. It should be lower than 30.
x + y < 30
The correct answer is option D
