Question

Sin^2x/cos^2 + sinxcscx = sec^2x Identify it, please explain so I know how you did it, thanks

Answer 1

$\frac{sin^2x}{cos^2x} + sin x *cscx\\ tan^2x + \frac{sin x}{sin x} \\ tan^2x + 1\\ sec^2x$

$\frac{sin^2x}{cos^2x} = tan^2x$

$csc x = \frac{1}{sinx}$

$tan^2x + 1 = sec^2x$