Answer:
225 m²
Step-by-step explanation:
If W is the width of the rectangle, and L is the length, then:
60 = 2W + 2L
A = WL
Use the first equation to solve for one of the variables:
30 = W + L
L = 30 − W
Substitute into the second equation:
A = W (30 − W)
A = 30W − W²
This is a parabola, so we can find the vertex using the formula x = -b/(2a).
W = -30 / (2 × -1)
W = 15
Or, we can use calculus:
dA/dW = 30 − 2W
0 = 30 − 2W
W = 15
Solving for L:
L = 30 − W
L = 15
So the maximum area is:
A = WL
A = (15)(15)
A = 225
Answer:
D.3.5
Step-by-step explanation:
4x+2y=10(given)
2x+y=5
y=5-2x-----(1)
y=2x-1------(2)(given)
Since the left side of the equations are the the same,
5-2x=2x-1
4x=6
x=1.5
Sub x=1.5 into eq(1),
y = 5-2(1.5) = 5-3 = 2
so, x+y = 1.5+2 = 3.5
If you would like to increase £84 by 3%, you can calculate this using the following steps:
3% * £84 = 3/100 * 84 = £2.52
£84 + £2.52 = £86.52
The correct result is £86.52.
Question 6
Given:
QR = RS
QR = x + 6
RS = 4x
To find:
Length of line segment QS
Steps:
We know QR = RS, so substituting we get,
x + 6 = 4x
6 = 4x - x
6 = 3x
6/3 = x
2 = x
x = 2
Now,
QS = QR + RS
QS = x + 6 + 4x
QS = 2 + 6 + 4(2)
QS = 2 + 6 + 8
QS = 8 + 8
QS = 16 units
Therefore, the length of QS is 16 units
Question 7
Given:
QR = RS
QR = 2x - 2
RS = 2x
To find:
Length of line segment QS
Steps:
We know that QR = RS, so substituting the values we get,
QR = RS
3x - 2 = 2x
3x - 2 - 2x = 0
3x - 2x = 2
x =2
Now,
QS = QR + RS
QS = 3x - 2 + 2x
QS = 3(2) - 2 + 2(2)
QS = 6 - 2 + 2(2)
QS = 6 - 2 + 4
QS = 4 + 4
QS = 8 units
Therefore, the length of QS is 8 units
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Answer:
a letter in a math problem
