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2 years ago

The slope of a line passing through H (-2, 5) is -3/4. Which ordered pair represents a point on this line?

1 answer:

5 0

Answer:
(6,-1)

Explanation:
The slope of the line can be calculated using the following formula:
slope = $\frac{y2-y1}{x2-x1}$

We are given that:
slope = -0.75
point (x1,y1) is (-2,5)

We will use each of the given points to calculate the corresponding slope, then compare the calculated slope with the given one.

For point (6,-1):
slope = $\frac{-1-5}{6--2}$ = -0.75 ........> accepted choice

For point (2,8):
slope = $\frac{8-5}{2--2}$ = 0.75 ........> rejected choice

For point (-5,1):
slope = $\frac{1-5}{-5--2}$ = 4/3 ........> rejected choice

For point (1,1):
slope = $\frac{1-5}{1--2}$ = -4/3 ........> rejected choice

Therefore, the first option is the only correct one.

Hope this helps :)

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Identify next three numbers in this sequence: 2, 6, 3, 9, 6, 18, 15

kherson [118]

Answer:

45,42,126

multiply by 3

6 0

3 years ago

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

2 years ago

What's the next step to substitution for this equation -4+y=-4

Marina86 [1]

Subtract the y then add the 4 to the other side so y=0

6 0

3 years ago

What is the value of x? Enter your answer, as a decimal, in the box.<br><br> ___ cm

lora16 [44]

Answer

50.6

Step-by-step explanation:

I'm not sure how to do it, but I took the quiz and it said this was the correct answer

6 0

3 years ago

If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (u/v)(x)

choli [55]

Answer:

c) -x^3 + x^2 - 1

Step-by-step explanation:

Given: u (x) = x^5 - x^4 +x^2 and v(x) = -x^2

(u/v)(x) = u(x)/v(x)

Now plug in the given functions in the above formula, we get

= (x^5 - x^4 + x^2) / -x^2

We can factorize the numerator.

In x^5 - x^4 + x^2. the common factor is x^2, so we can take it out and write the remaining terms in the parenthesis.

= x^2 (x^3 - x^2 + 1) / - x^2

Now we gave x^2 both in the numerator and in the denominator, we can cancel it out.

(u/v)(x) = (x^3 - x^2 + 1) / -1

When we dividing the numerator by -1, we get

(u/v)(x) = -x^3 + x^2 - 1

Answer: c) -x^3 + x^2 - 1

Hope you will understand the concept.

Thank you.

6 0

3 years ago

Read 2 more answers