There are 3 choices for the bottom scoop. Then there are only 3 choices for the scoop above that (since one flavor has already been used), then 2 choices for the next scoop, and 1 choice for the final scoop. This gives a total of 18 <span>possible cones.
Hope this helps.
</span>
Lets use x to represent the cheese wafers and y to represent the chocolate wafers.
For part A:
The system of equation would be:
x+y=20 (this equation represents how many were bought)
2x+y=25 (the price. Remember that there is an imaginary 1 in front of the y)
For Part B:
To find how many chocolate wafers were bought, isolate y in the first equation (x+y=20) by bringing y to the other side. You are left with x= 20-y.
Plug the new equation into the second equation (2x+y=25) for x.
Now solve:
Step 1 (Plug in): 2(20-y)+y=25
Step 2 (Distribute): 40-2y+y=25
Step 3 (Combine like terms): 40-y=25
Step 4 (Subtract 40 from each side of the equation): -y=-15
Step 5 (divide by -y): y=15
Therefore, a total of 15 chocolate wafers were bought. This means that a total of 5 cheese wafers were bought. I got the answer by solving for variables. I selected these particular method, because it is the easiest and most efficient way of solving this problem (in my opinion). Hope I help :). If you have any questions please let me know.
Answer:
10
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
x=12358
y=234678
(x u y)'
=(12345678)'
=91012