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Misha Larkins [42]
2 years ago
8

Aaron wants to make All-Tournament Team for his high school

Mathematics
2 answers:
bazaltina [42]2 years ago
8 0

Answer:

Step-by-step explanation:

Rus_ich [418]2 years ago
6 0

Answer:24

Step-by-step explanation:

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How do you simply the square root of 28
maria [59]
\sqrt{28} can be rewritten as ;
=\sqrt{7*4}
=\sqrt{4} * \sqrt{7}
=2\sqrt{7}
3 0
3 years ago
Given the right triangle shown below.if Cos A =15/17 and tan A=8/15 which of the following represents the length of BC
otez555 [7]

Answer:

The Figure for Right triangle is below,

Therefore , 15 unit length represents BC.

Step-by-step explanation:

Given:

Consider a right triangle ABC, Such that

\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15}

To Find:

BC = ?

Solution:

In Right Angle Triangle ABC, Cosine and Tangent identity

\cos A = \dfrac{\textrm{side adjacent to angle C}}{Hypotenuse}\\

\tan A= \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}

BUT,

\cos A=\dfrac{15}{17}\\\\\tan A=\dfrac{8}{15} ....Given

On Comparing,

Adjacent side to angle A = AB = 15

Opposite side to angle A = BC = 8

Hypotenuse = AC =17

Also Pythagoras theorem is Satisfies,

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

(\textrm{Hypotenuse})^{2} = 17^{2}=289

(\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}=15^{2}+8^{2}=289

The Figure for Right triangle is below,

Therefore , 15 unit length represents BC.

7 0
3 years ago
Consider the differential equation y'' − y' − 30y = 0. Verify that the functions e−5x and e6x form a fundamental set of solution
Alex Ar [27]

Answer:

Step-by-step explanation:

We have to take the derivatives for both functions and replace in the differential equation. Hence

for y=e^{-5x}:

y(x)=e^{-5x}\\y'(x)=-5e^{-5x}\\y''(x)=25e^{-5x}\\

for y=e^{6x}:

y(x)=e^{6x}\\y'(x)=6e^{6x}\\y''(x)=36e^{6x}\\

Now we replace in the differential equation  y'' − y' − 30y = 0

for y=e^{-5x}:

25e^{-5x}+5e^{-5x}-30e^{-5x}=0\\25+5-30=0

for y=e^{6x}:

36e^{6x}-6e^{6x}-30=0\\36-6+30=0

Now, to know if both function are linearly independent we calculate the Wronskian

W(f,g)=fg'-f'g

W(e^{-5x},e^{6x})=(e^{-5x})(6e^{6x})-(-5e^{-5x})(e^{6x})\neq 0

I hope this is useful for you

Best regard

7 0
3 years ago
Madeline deposited $750 into an investment account that earns 1.5% interest compounded annually. If no deposits nor withdrawals
mash [69]
B $937.67 is the correct answer
7 0
3 years ago
47.93 to the nearest tenth
erastova [34]
47.90 is your answer to the nearest tenths
8 0
3 years ago
Read 2 more answers
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