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natulia [17]
3 years ago
14

Liliana decides to crop a square photo 2 inches on each side to fit it into a frame. The area of the original photo was 121 squa

re inches. In the equation (x + 2)2 = 121, x represents the side measure of the cropped photo.
What are the dimensions of the cropped photo?

A. 8 inches by 8 inches
B. 9 inches by 9 inches
C. 12 inches by 12 inches
D. 13 inches by 13 inches
Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
6 0

Answer: B. 9 inches by 9 inches

x = -13 or x = 9

x cannot be negative, so

x = 9 inches

Therefore, the dimensions of the cropped photo is 9 inches by 9 inches.

Liliana decides to crop a square photo 2 inches on each side to fit it into a frame. The area of the original photo was 121 square inches. In the equation (x + 2)^2 = 121, x represents the side measure of the cropped photo.

What are the dimensions of the cropped photo?

A. 8 inches by 8 inches

B. 9 inches by 9 inches

C. 12 inches by 12 inches

D. 13 inches by 13 inches

Step-by-step explanation:

Given that;

(x+2)^2 = 121. ....1

x = size of cropped picture.

To solve for x,

From eqn1

x^2 + 4x + 4 = 121

x^2 + 4x - 117 = 0

Solving the quadratic equation gives;

(x+13)(x-9) = 0

x = -13 or x = 9

x cannot be negative, so

x = 9 inches

Therefore, the dimensions of the cropped photo is 9 inches by 9 inches.

mixer [17]3 years ago
6 0

Answer:

B. 9 inches by 9 inches

Step-by-step explanation:

he formula for the area of a square is length x width

For a square the length and the width are same therefore it is  

length x length = (length)²  (let’s call this first equation)

also (x + 2 )²= 121        (let’s call this second equation)

To form an equation for the cropped picture from the original picture

Length = (cut off length + new length) (third equation)

Length = ( 2 + x)           fourth equation

assuming the new lenght is x

Since 2 is the cut off length from each sides

Lets substitute first equation into second equation then we will have

Lenght² = 121

Length = √121

Length = 11

Substitute into fourth equation

Length = 11 = (x+2)

X+2 =11

X= 11 - 2

X=9

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<h3>How to find the points of intersection?</h3>

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Answer:

Part 1) The graph has three (3) x-intercepts and  has one (1) y-intercept

Part 2) The y-value of the minimum point is -3

Part 3) f(4)=3

Part 4) f(0)=3

Part 5) f(5)=1.5

Part 6) x=-6

Part 7) The horizontal line y=-1 intersects the graph three times

Part 8) The value of the function for f(6) is equal to zero

Part 9) The function is increasing on the interval (-6,-2) and (8,11) and the function is decreasing on the interval (2,8)

Part 10) The function is positive on the interval (-3,6) and (10,11) and is negative on the interval (-6,-3) and (6,10)

Step-by-step explanation:

Part 1) Find the number of x-intercepts and y-intercepts of the graph

we know that

The<u> x-intercepts</u> are the values of x when the value of y (the function) is equal to zero

Look at the graph

The graph has 3 x-intercepts

The x-intercepts are the points (-3,0), (6,0) and (10,0)

The<u> y-intercepts</u> are the values of y when the value of x is equal to zero

Look at the graph            

The graph has 1 y-intercept

The y-intercept is the point (0,3)

Part 2) The y value of the minimum point on the graph is?

we know that

Look at the picture

The minimum point is (-6,-3)

therefore

The y-value of the minimum point is -3

Part 3)  f(4) is equal to?

we know that

f(4) is the value of the function when the value of x is equal to 4

Look at the graph

For x=4

The value of the function is equal to y=3

therefore

f(4)=3

Part 4) f(0) is equal to?

we know that

f(0) is the value of the function when the value of x is equal to 0

Look at the graph

For x=0

The value of the function is equal to y=3

therefore

f(0)=3

Part 5) f(5) is equal to?

we know that

f(5) is the value of the function when the value of x is equal to 5

Look at the graph

For x=5

The value of the function is about y=1.5  (see the attached figure)

therefore

f(5)=1.5

Part 6) The value of x when f(x)= -3 is?

Look at the graph

we have the point (-6,-3)

when the value of f(x)=-3

the value of x is equal to x=-6

Part 7) The horizontal line y = -1 intersects the graph _____ times?

Look at the graph

The horizontal line y=-1 intersects the graph three times (see the attached figure)

Part 8) f(6) is positive or negative?

Look at the graph

we have the point (6,0)

For x=6

The value of the function is equal to zero

Part 9) Is the graph increasing or decreasing on the interval -6?

Look at the graph

The function is increasing on the interval (-6,-2) and (8,11) and the function is decreasing on the interval (2,8)

Part 10) Is the graph positive or negative on the interval 6

Look at the graph

The function is positive (f(x) > 0) on the interval (-3,6) and (10,11) and is negative (f(x) < 0) on the interval (-6,-3) and (6,10)

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